Solve the factored quadratic equation (19x−3)(9+x)=0
To solve the factored quadratic equation (19x-3)(9+x)=0, we can set each factor equal to zero and solve for x.
Setting 19x - 3 = 0:
19x = 3
x = 3/19
Setting 9 + x = 0:
x = -9
Therefore, the solutions to the equation (19x-3)(9+x)=0 are x = 3/19 and x = -9.
To solve the factored quadratic equation (19x - 3)(9 + x) = 0, you can use the zero product property. According to this property, if a product of factors is equal to zero, then at least one of the factors must be equal to zero.
So, we set each factor equal to zero and solve for x:
1) 19x - 3 = 0:
Adding 3 to both sides, we get:
19x = 3
Dividing both sides by 19, we get:
x = 3/19
2) 9 + x = 0:
Subtracting 9 from both sides, we get:
x = -9
Therefore, the solutions to the equation (19x - 3)(9 + x) = 0 are x = 3/19 and x = -9.
To solve the factored quadratic equation (19x−3)(9+x) = 0, you can use the zero product property, which states that if a product of factors is equal to zero, then at least one of the factors must be equal to zero.
In this case, we have two factors, (19x−3) and (9+x), so we can set each factor separately equal to zero and solve for x.
Setting the first factor equal to zero:
19x − 3 = 0
Add 3 to both sides of the equation:
19x = 3
Divide both sides by 19:
x = 3/19
Setting the second factor equal to zero:
9 + x = 0
Subtract 9 from both sides of the equation:
x = -9
Therefore, the solutions to the given factored quadratic equation are x = 3/19 and x = -9.