For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
8(x − 6) = 48
8 left parenthesis x minus 6 right parenthesis equals 48
6x − 8 = 48
6 x minus 8 equals 48
6(x + 8) = 48
6 left parenthesis x plus 8 right parenthesis equals 48
6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48
The equation for which the order of steps is to first divide both sides by 6 and then to add 8 to both sides is:
6(x - 8) = 48
The equation for which the order of steps is to first divide both sides by 6 and then to add 8 to both sides is:
6(x − 8) = 48
To determine this, we need to analyze the steps for each equation:
1) 8(x − 6) = 48
- This equation requires different steps. We would start by distributing the 8 to the terms inside the parentheses before applying any other operations.
2) 6x − 8 = 48
- In this equation, we would begin by adding 8 to both sides to isolate the term 6x. After that, we can divide both sides by 6 to solve for x.
3) 6(x + 8) = 48
- Again, we need to distribute the 6 to the terms inside the parentheses first. This equation doesn't match the given order of operations.
4) 6(x − 8) = 48
- This equation aligns with the given order of steps. First, we divide both sides by 6 to isolate the term x − 8. Later, we can add 8 to both sides to solve for x.
Therefore, the correct equation is 6(x − 8) = 48.