The set of ordered pairs represents a function.
(0, 2), (1, 3), (2, 4), (3, 5), (4, 6)
True
If the above set of ordered pairs is a function, is it a linear or a nonlinear function?
O The set of ordered pairs was not a function.
O The set of ordered pairs is a linear function.
O The set of ordered pairs is a nonlinear function.
O The set of ordered pairs is neither a linear nor nonlinear function.
The set of ordered pairs is a linear function, because the y-values increase by a constant amount (1) for each increase in the x-values.
To determine if the set of ordered pairs is a linear or nonlinear function, we can examine the pattern of the points.
In this case, the set of ordered pairs shows a consistent increase of 1 for the second value (the y-values) as the first value (the x-values) increases by 1.
(0, 2), (1, 3), (2, 4), (3, 5), (4, 6)
Since the y-values are increasing by a constant rate as the x-values increase, we can conclude that the set of ordered pairs represents a linear function.
Therefore, the correct answer is: The set of ordered pairs is a linear function.
To determine if the given set of ordered pairs represents a function, we need to check if each input value (x-coordinate) is associated with exactly one output value (y-coordinate). If this condition is satisfied, then the set is a function.
Let's examine the given set:
(0, 2), (1, 3), (2, 4), (3, 5), (4, 6)
We can see that each input value is associated with a unique output value, meaning there are no repeated x-values. Therefore, the given set of ordered pairs does represent a function.
Now, to determine if the function is linear or nonlinear, we need to examine the pattern in the y-values as the x-values increase.
In this case, as the x-values increase by 1, the y-values also increase by 1 (e.g., from 2 to 3, 3 to 4, and so on). This indicates a constant rate of change, which is a characteristic of linear functions.
Therefore, the set of ordered pairs represents a linear function.
The correct answer is:
The set of ordered pairs is a linear function.