One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?
a
2
b
6
c
4
d
3
c) 4
To determine the number of atoms in the products, we first need to write out the balanced chemical equation for the reaction:
I2 + 2 NaCl -> 2 NaI + Cl2
From the equation, we can see that 1 molecule of Iodine (I2) reacts with 2 molecules of sodium chloride (NaCl).
In the products, we have 2 molecules of sodium iodide (NaI) and 1 molecule of chlorine gas (Cl2).
To find the number of atoms in each molecule of the products, we need to know the chemical formula of each compound.
NaI contains 1 sodium (Na) atom and 1 iodine (I) atom per molecule. Therefore, 2 molecules of NaI would contain 2 sodium atoms and 2 iodine atoms.
Cl2 contains 2 chlorine (Cl) atoms per molecule. Therefore, 1 molecule of Cl2 contains 2 chlorine atoms.
Adding up the number of atoms in the products, we have:
- 2 sodium atoms
- 2 iodine atoms
- 2 chlorine atoms
Therefore, the correct answer is a) 2. There are 2 atoms in the products.
To determine the number of atoms in the products, we need to calculate the total number of atoms present in each molecule and then add them up.
Starting with Iodine (I2), each molecule contains 2 iodine atoms. Therefore, in 1 molecule of iodine, we have 2 atoms.
Next, considering sodium chloride (NaCl), each molecule contains 1 sodium atom (Na) and 1 chlorine atom (Cl). So, in 2 molecules of sodium chloride, we have 2 sodium atoms (2 Na) and 2 chlorine atoms (2 Cl). Adding those up, we have a total of 2 + 2 = 4 atoms.
Therefore, the correct answer is c) 4.