For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)
Responses
6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48
8(x − 6) = 48
8 left parenthesis x minus 6 right parenthesis equals 48
6x − 8 = 48
6 x minus 8 equals 48
6(x + 8) = 48
6 left parenthesis x plus 8 right parenthesis equals 48
The equation for which the order of steps is to first divide both sides by 6 and then add 8 to both sides is:
6(x - 8) = 48
To determine which equation requires dividing both sides by 6 first and then adding 8 to both sides, we need to look at the equations and identify the step-by-step operations.
Let's break down the equations one by one:
1. 6(x - 8) = 48
For this equation, we have parentheses, so the first step would be to simplify the expression inside the parentheses by multiplying 6 with (x - 8). After simplifying, we would have:
6x - 48 = 48
2. 8(x - 6) = 48
Similar to the first equation, we have parentheses, so the first step would be to simplify the expression inside the parentheses by multiplying 8 with (x - 6). After simplifying, we would have:
8x - 48 = 48
3. 6x - 8 = 48
In this equation, there are no parentheses, so we don't need to perform any simplification. The next step would be to add 8 to both sides:
6x - 8 + 8 = 48 + 8
This simplifies to:
6x = 56
4. 6(x + 8) = 48
As with the previous equations, we simplify the expression inside the parentheses by multiplying 6 with (x + 8). After simplifying, we get:
6x + 48 = 48
Based on the order of steps mentioned in the question, the equation that requires dividing both sides by 6 first and then adding 8 to both sides is equation #3:
6x - 8 = 48