Light travels at an approximate rate of 1.9. x 10^5 mi/sec. There are about 3.2 x 10^7 seconds in a year. About how many miles does light travel in a year? Write the answer in scientific notation. Express the answer to the exact decimal place.
To find the number of miles light travels in a year, we multiply the rate of light by the number of seconds in a year:
1.9 x 10^5 mi/sec * 3.2 x 10^7 sec/year
To multiply these numbers, we add their exponents and multiply their coefficients:
(1.9 * 3.2) * (10^5 * 10^7) mi
6.08 * 10^(5+7) mi
6.08 * 10^12 mi
In scientific notation, light travels approximately 6.08 x 10^12 miles in a year.
To find out how many miles light travels in a year, we can multiply the speed of light by the number of seconds in a year.
Speed of light = 1.9 x 10^5 mi/sec
Number of seconds in a year = 3.2 x 10^7 seconds
Multiplying these two values gives us:
(1.9 x 10^5 mi/sec) * (3.2 x 10^7 seconds)
To multiply the numbers in scientific notation, we multiply the coefficients (1.9 * 3.2) and add the exponents (5 + 7):
= (1.9 * 3.2) * (10^5 * 10^7)
= 6.08 * 10^12
Therefore, light travels approximately 6.08 x 10^12 miles in a year.
To find out how many miles light travels in a year, we can multiply the speed of light by the number of seconds in a year.
The speed of light is given as 1.9 x 10^5 mi/sec.
The number of seconds in a year is given as 3.2 x 10^7 seconds.
To multiply numbers in scientific notation, we can multiply the coefficients (1.9 and 3.2) and add the exponents (5 and 7) to get the final answer.
1.9 x 3.2 = 6.08
10^5 x 10^7 = 10^(5+7) = 10^12
Combining the coefficient and exponent, the answer is 6.08 x 10^12 mi.
Therefore, light travels approximately 6.08 x 10^12 miles in a year.
The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 x 10^6 years? Write the answer in scientific notation, expressed to the exact decimal place.
To find the number of meters the tectonic plate would move in 2 x 10^6 years, we multiply the rate of movement (0.006 m/year) by the number of years:
0.006 m/year * 2 x 10^6 years
To multiply these numbers, we multiply their coefficients and add their exponents:
(0.006 * 2) * (10^6 m * 1 year)
0.012 * 10^6 m
To express this answer in scientific notation to the exact decimal place, we multiply the coefficient by 10 and decrease the exponent by 1:
1.2 * 10^5 m
Therefore, the tectonic plate would move approximately 1.2 x 10^5 meters in 2 x 10^6 years.