Imagine a scenario in which an animal's force is pushing itself forward 5 N, friction is pushing it 4 N backward, gravity is pushing the animal 10 N down, and the animal is pushing itself 10 N up. Describe the movement of the animal.(1 point)
Responses
It moves forward and upward because those are the greatest net forces.
It moves forward and upward because those are the greatest net forces.
It moves 29 N forward because that's the net force.
It moves 29 N forward because that's the net force.
It only moves forward because there is a net force forward.
It only moves forward because there is a net force forward.
It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.
It moves forward and upward because those are the greatest net forces.
The correct response is: It moves forward and upward because those are the greatest net forces.
The correct response is: It moves forward and upward because those are the greatest net forces.
To determine the movement of the animal, we need to calculate the net force acting on it. Net force is the sum of all the forces acting on an object. In this scenario, the animal's force pushing itself forward is 5 N, friction is pushing it backward with a force of 4 N, gravity is pushing it down with a force of 10 N, and the animal is pushing itself upward with a force of 10 N.
To calculate the net force, we first need to determine the forces in the x and y directions separately.
In the x direction, the animal's force pushing itself forward is 5 N, and friction is pushing it backward with a force of 4 N. The net force in the x direction is:
Net force in x direction = Force pushing forward - Force pushing backward = 5 N - 4 N = 1 N
In the y direction, the animal is pushing itself upward with a force of 10 N, and gravity is pushing it down with a force of 10 N. The net force in the y direction is:
Net force in y direction = Force pushing upward - Force pushing downward = 10 N - 10 N = 0 N
Now, we can combine the net forces in the x and y directions to determine the overall net force:
Net force = sqrt((Net force in x direction)^2 + (Net force in y direction)^2) = sqrt((1 N)^2 + (0 N)^2) = sqrt(1 N^2) = 1 N
Since the net force is 1 N forward, the animal will move in the forward direction. Additionally, since the net force in the y direction is 0 N (equal forces pushing upward and downward), the animal will not move vertically.
Therefore, the correct response is that the animal moves forward and upward because those are the greatest net forces.