If you crossed a homozygous (BB) guinea pig for black fur color with a heterozygous (Bb) guinea pig for black fur color, what would be the predicted percentage of homozygous, black-furred guinea pigs?(1 point)
Responses
100%
100%
75%
75%
25%
25%
50%
50%
50%
To determine the predicted percentage of homozygous, black-furred guinea pigs, you need to consider the genetic inheritance pattern of fur color in guinea pigs.
In this case, "B" represents the dominant allele for black fur color, while "b" represents the recessive allele for non-black fur color. The homozygous guinea pig (BB) has two copies of the dominant allele, and the heterozygous guinea pig (Bb) has one copy of the dominant allele and one copy of the recessive allele.
When these two guinea pigs are crossed, the possible outcomes for the offspring are as follows:
- 50% chance of inheriting the dominant allele from the homozygous guinea pig (BB), resulting in black fur (BB)
- 50% chance of inheriting the dominant allele from the heterozygous guinea pig (Bb), resulting in black fur (Bb)
Therefore, the predicted percentage of homozygous, black-furred guinea pigs is 50%.
The predicted percentage of homozygous, black-furred guinea pigs can be determined using the Punnett square method.
When crossing a homozygous (BB) guinea pig for black fur color with a heterozygous (Bb) guinea pig for black fur color, the possible genotypes of the offspring are BB (black fur) and Bb (black fur).
To calculate the percentage of homozygous, black-furred guinea pigs, we need to determine the number of offspring with the genotype BB compared to the total number of offspring.
In this case, there are two possible genotypes (BB and Bb), and one out of the two genotypes (BB) represents the homozygous, black-furred guinea pigs.
Therefore, the predicted percentage of homozygous, black-furred guinea pigs is:
BB / (BB + Bb) = 1 / (1 + 1) = 1/2 = 50%
So the correct answer is 50%.