Jennifer's basketball team played 18 games this season, and they won twice as many games as they lost. How many games did they lose?
Responses
A 66
B 99
C 1212
D 1515
E 17
If Jennifer's basketball team won twice as many games as they lost, let's assume they lost x games.
Accordingly, they won 2x games.
The total number of games played is x + 2x = 18.
Combining like terms, we get 3x = 18.
Dividing both sides of the equation by 3, we find that x = 6.
Therefore, they lost 6 games. Answer choice E is correct.
Let's analyze the information given. Jennifer's basketball team played 18 games this season, and they won twice as many games as they lost.
Let's assume the number of games they lost is x.
According to the information given, the number of games they won is twice the number of games they lost, which is 2x.
So, the total number of games Jennifer's team played can be expressed as:
x + 2x = 18
Combining like terms, we have:
3x = 18
Dividing both sides of the equation by 3, we get:
x = 6
Therefore, Jennifer's basketball team lost 6 games.
Answer: They lost 6 games.
To determine how many games Jennifer's basketball team lost, we need to compare the number of games they won to the total number of games played.
We are given that Jennifer's basketball team won twice as many games as they lost. Let's denote the number of games they lost as "L". Therefore, the number of games they won can be written as 2 * L.
The total number of games played is given as 18. So we can write the equation:
2 * L + L = 18
Combining like terms, we get:
3L = 18
To solve for L, we divide both sides of the equation by 3:
L = 18 / 3
L = 6
Therefore, Jennifer's basketball team lost 6 games.
Thus, the correct answer is E) 6.