Consider the function g(x) = 2 3x+1. Evaluate g(x) to find the range for the domain (-2, -1, 0)
To find the range of the function, we need to evaluate g(x) for each value in the domain (-2, -1, 0).
First, let's evaluate g(-2):
g(-2) = 2 * (3(-2) + 1)
= 2 * (-6 + 1)
= 2 * (-5)
= -10
So, g(-2) = -10.
Next, let's evaluate g(-1):
g(-1) = 2 * (3(-1) + 1)
= 2 * (-3 + 1)
= 2 * (-2)
= -4
So, g(-1) = -4.
Lastly, let's evaluate g(0):
g(0) = 2 * (3(0) + 1)
= 2 * (0 + 1)
= 2 * 1
= 2
So, g(0) = 2.
The range of the function g(x) for the domain (-2, -1, 0) is {-10, -4, 2}.
To evaluate the function g(x), we substitute each value in the domain (-2, -1, 0) into the equation g(x) = 2(3x+1) step by step:
For x = -2:
g(-2) = 2(3(-2)+1)
= 2(-6+1)
= 2(-5)
= -10
For x = -1:
g(-1) = 2(3(-1)+1)
= 2(-3+1)
= 2(-2)
= -4
For x = 0:
g(0) = 2(3(0)+1)
= 2(0+1)
= 2(1)
= 2
Therefore, the range of the function g(x) for the given domain (-2, -1, 0) is {-10, -4, 2}.
To evaluate the function g(x) for the given domain values (-2, -1, 0), we substitute each value into the function and compute the corresponding outputs.
Let's start with x = -2:
g(-2) = 2(3(-2) + 1)
= 2(-6 + 1)
= 2(-5)
= -10
Now, let's evaluate g(x) for x = -1:
g(-1) = 2(3(-1) + 1)
= 2(-3 + 1)
= 2(-2)
= -4
Lastly, let's find the value of g(x) for x = 0:
g(0) = 2(3(0) + 1)
= 2(0 + 1)
= 2(1)
= 2
Therefore, the range for the domain (-2, -1, 0) is {-10, -4, 2}.