Find the normality of 0.321 g sodium carbonate in a 250 mL solution.
To find the normality of a solution, we need to know the number of moles of the solute present in the given volume.
First, we need to calculate the number of moles of sodium carbonate.
The molar mass of sodium carbonate (Na2CO3) is:
Na: 22.99 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
To calculate the molar mass of sodium carbonate:
(2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol) = 46.00 g/mol + 12.01 g/mol + 48.00 g/mol = 106.01 g/mol
Next, we convert the given mass of sodium carbonate (0.321 g) to moles using the molar mass:
0.321 g / 106.01 g/mol = 0.00303 mol
Now, we need to find the number of moles in the given volume.
The volume is given as 250 mL, but we need to convert it to liters:
250 mL = 250 mL / 1000 mL/L = 0.25 L
Finally, we can calculate the normality by dividing the number of moles by the volume in liters:
Normality = 0.00303 mol / 0.25 L ≈ 0.0121 N
Therefore, the normality of the solution is 0.0121 N.
To find the normality of a solution, we first need to calculate the number of moles of the solute, sodium carbonate (Na2CO3).
Step 1: Calculate the number of moles of sodium carbonate (Na2CO3):
To do this, we need to know the molar mass of sodium carbonate.
- The molar mass of Na (sodium) = 22.99 g/mol
- The molar mass of C (carbon) = 12.01 g/mol
- The molar mass of O (oxygen) = 16.00 g/mol
The molar mass of sodium carbonate (Na2CO3) can be calculated as follows:
(2 * molar mass of Na) + molar mass of C + (3 * molar mass of O) = (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol
Now, we can calculate the moles of sodium carbonate:
moles = mass / molar mass
moles = 0.321 g / 105.99 g/mol ≈ 0.00303 mol
Step 2: Convert the volume of the solution to liters:
The volume of the solution is given as 250 mL, but we need it in liters for the calculation.
volume (L) = 250 mL / 1000 mL/L = 0.250 L
Step 3: Calculate normality:
Normality (N) is defined as the number of moles of solute per liter of solution.
normality = moles / volume (L)
normality = 0.00303 mol / 0.250 L ≈ 0.0121 N
Therefore, the normality of the sodium carbonate solution is approximately 0.0121 N.
To find the normality of a solution, you will need to know the number of equivalents of the solute in a given volume of the solution.
To calculate the normality, you will first need to determine the number of moles of sodium carbonate in the given mass and convert it to equivalents.
To do that, you need to follow these steps:
Step 1: Calculate the molar mass of sodium carbonate (Na2CO3):
The molar mass of Na2CO3 is calculated by adding the atomic masses of each element:
2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol.
Step 2: Convert the given mass of sodium carbonate to moles:
To convert grams to moles, divide the given mass by the molar mass:
0.321 g / 105.99 g/mol = 0.00303 moles.
Step 3: Calculate the number of equivalents:
The number of equivalents is equal to the total number of moles multiplied by the number of equivalents per mole. For sodium carbonate, there are two equivalents of sodium ions (Na+) and one equivalent of carbonate ions (CO3 2-). Therefore, the total number of equivalents is:
0.00303 moles * (2 equivalents/1 mole) = 0.00606 equivalents.
Step 4: Calculate normality:
Finally, divide the number of equivalents (0.00606) by the volume of the solution in liters (250 mL converted to liters is 0.250 L):
Normality = 0.00606 equivalents / 0.250 L = 0.02424 N.
Therefore, the normality of the 0.321 g sodium carbonate in a 250 mL solution is 0.02424 N.