Sodium reacts with chlorine to form the compound sodium chloride, or salt. The chemical formula below shows how two elements combine into a compound.

2Na + Cl2 → 2NaCI
If the total mass of the reactants is 58.44 amu, what will be the total mass of the products?
(1 point)
58.44 amu
60 amu
116.88 amu
29.22 amu

The balanced equation tells us that 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCI.

To find the total mass of the products, we need to calculate the molar mass of NaCl. Na has a molar mass of 22.99 g/mol, and Cl has a molar mass of 35.45 g/mol.

So, the molar mass of NaCl is:
(2 mol Na x 22.99 g/mol) + (2 mol Cl x 35.45 g/mol) = 45.98 g + 70.9 g = 116.88 g/mol.

Given that the total mass of reactants is 58.44 amu, we can assume that the total mass of the products will also be 58.44 amu.

Therefore, the correct answer is 58.44 amu.

To determine the total mass of the products, we need to find the molar mass of NaCl, which is the product formed.

The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol.

Using the balanced chemical equation:
2Na + Cl2 → 2NaCl

We see that 2 moles of Na react with 1 mole of Cl2 to form 2 moles of NaCl.

So, the molar mass of NaCl is:
(2 x molar mass of Na) + (1 x molar mass of Cl2)
= (2 x 22.99 g/mol) + (1 x 35.45 g/mol)
= 45.98 g/mol + 35.45 g/mol
= 81.43 g/mol

Now, let's calculate the total mass of the products by multiplying the molar mass of NaCl by the number of moles formed.

Total mass of the products = molar mass of NaCl x number of moles of NaCl

Since the balanced equation shows that 2 moles of NaCl are formed for every 2 moles of Na, the number of moles of NaCl will be equal to the number of moles of Na.

Therefore, the total mass of the products can be calculated as:
Total mass of the products = 81.43 g/mol x number of moles of Na
= 81.43 g/mol x 1 (since the total mass of reactants is given as 58.44 amu, which can be converted to g/mol)

Hence, the total mass of the products will be 81.43 g/mol.

However, since the options provided are in amu, we need to convert the mass to amu.

The molar mass of sodium chloride (NaCl) is 81.43 g/mol.

1 g/mol is equal to 1 amu, so the total mass of the products will be 81.43 amu.

Therefore, the correct answer is:
116.88 amu.

To find the total mass of the products, we need to understand the concept of conservation of mass. According to this principle, mass is neither created nor destroyed during a chemical reaction. In other words, the total mass of the reactants should be equal to the total mass of the products.

In the given chemical equation, we can see that we have 2 moles of sodium (Na) reacting with 1 mole of chlorine (Cl2) to produce 2 moles of sodium chloride (NaCl). To calculate the total mass of the products, we need to sum up the masses of the individual elements present in the products.

The atomic mass of sodium (Na) is 22.99 amu, while the atomic mass of chlorine (Cl) is 35.45 amu. Since there are 2 moles of sodium reacting, the total mass of sodium in the products is:

2 moles x (22.99 amu/mole) = 45.98 amu

Similarly, since there is 1 mole of chlorine reacting, the total mass of chlorine in the products is:

1 mole x (35.45 amu/mole) = 35.45 amu

Finally, we can add up the masses of sodium and chlorine to obtain the total mass of the products:

Total mass of products = mass of sodium + mass of chlorine
= 45.98 amu + 35.45 amu
= 81.43 amu

Therefore, the total mass of the products is 81.43 amu.

Among the answer choices given, none of them is 81.43 amu. This suggests that there might be an error in the question or the answer choices.