The sum of three consecutive integers is -42 find the three integers
Let's call the first integer x.
The next consecutive integer would be x + 1, and the one after that would be x + 2.
According to the problem, the sum of these three integers is -42, so we can set up an equation:
x + (x + 1) + (x + 2) = -42
Combining like terms:
3x + 3 = -42
Subtracting 3 from both sides:
3x = -45
Dividing by 3:
x = -15
Therefore, the three integers are -15, -14, and -13.
Let's say the three consecutive integers are x, x+1, and x+2.
According to the problem, the sum of these three integers is -42. So we can write the equation:
x + (x + 1) + (x + 2) = -42
Simplifying the equation:
3x + 3 = -42
Subtracting 3 from both sides:
3x = -45
Dividing both sides by 3:
x = -45/3
Simplifying further:
x = -15
So the three consecutive integers are -15, -14, and -13.
To find the three consecutive integers, we can use algebraic expressions.
Let's assume that the first integer is x. Then, the next two consecutive integers would be (x + 1) and (x + 2).
According to the given information, the sum of these three integers is -42. This can be represented as:
x + (x + 1) + (x + 2) = -42
Now, let's solve the equation to find the value of x:
3x + 3 = -42
3x = -42 - 3
3x = -45
x = -45 / 3
x = -15
So the first integer (x) is -15.
Now, we can find the other two consecutive integers by substituting the value of x:
First integer: x = -15
Second integer: x + 1 = -15 + 1 = -14
Third integer: x + 2 = -15 + 2 = -13
Therefore, the three consecutive integers are -15, -14, and -13.