What is the specific heat of a substance that absorbs 2.5 x 10 3joules of heat when a sample of 1.0 x 10 4g of the substance increases in temperature from 10.0°C to 70.0°C?
The formula to calculate the specific heat is:
q = m * c * ΔT
where:
q is the heat absorbed/released (in joules),
m is the mass of the substance (in grams),
c is the specific heat (in J/g°C), and
ΔT is the change in temperature (in °C).
Given:
q = 2.5 x 10^3 J
m = 1.0 x 10^4 g
ΔT = (70.0°C - 10.0°C) = 60.0°C
Rearranging the equation:
c = q / (m * ΔT)
Calculating the specific heat:
c = (2.5 x 10^3 J) / (1.0 x 10^4 g * 60.0°C)
c ≈ 4.17 J/g°C
Therefore, the specific heat of the substance is approximately 4.17 J/g°C.
To find the specific heat of a substance, you can use the formula:
q = mcΔT
Where:
q = heat absorbed or released
m = mass of the substance
c = specific heat capacity of the substance
ΔT = change in temperature
In this case, we are given:
q = 2.5 x 10^3 J
m = 1.0 x 10^4 g
ΔT = (70.0°C - 10.0°C) = 60.0°C
Now we can substitute the given values into the formula and solve for c:
2.5 x 10^3 J = (1.0 x 10^4 g) * c * 60.0°C
To find c, we need to rearrange the formula:
c = (2.5 x 10^3 J) / (1.0 x 10^4 g * 60.0°C)
Calculating the equation:
c = 2.5 x 10^3 J / 1.0 x 10^4 g * 60.0°C
c = 0.0042 J/g°C
Therefore, the specific heat of the substance is 0.0042 J/g°C.
To find the specific heat of a substance, you can use the formula:
q = m * c * ΔT
- Where q is the amount of heat absorbed or released,
- m is the mass of the substance,
- c is the specific heat, and
- ΔT is the change in temperature.
In this case, we have:
q = 2.5 x 10^3 J (given)
m = 1.0 x 10^4 g (given)
ΔT = (70.0°C - 10.0°C) = 60.0°C
Plugging in the values into the formula, we get:
2.5 x 10^3 J = (1.0 x 10^4 g) * c * 60.0°C
Now, we can solve for c:
c = (2.5 x 10^3 J) / ((1.0 x 10^4 g) * 60.0°C)
First, let's convert the mass from grams to kilograms:
m = 1.0 x 10^4 g = 1.0 x 10^1 kg
Now, let's plug in the values:
c = (2.5 x 10^3 J) / ((1.0 x 10^1 kg) * 60.0°C)
c = (2.5 x 10^3 J) / (6.0 x 10^2 kg°C)
c ≈ 4.17 J / (kg°C)
Therefore, the specific heat of the substance is approximately 4.17 J/(kg°C).