How many atoms seven
seven
six
six
four
four
eightare represented in the formula Na2HPO4?
In the formula Na2HPO4, there are a total of 1 sodium atom (Na), 2 hydrogen atoms (H), 1 phosphorus atom (P), and 4 oxygen atoms (O). Therefore, there are a total of 1 + 2 + 1 + 4 = 8 atoms represented in the formula Na2HPO4.
To determine the number of atoms in the Na2HPO4 formula, we need to break it down and count the atoms for each element individually.
1. Na2HPO4 consists of sodium (Na), hydrogen (H), phosphorus (P), and oxygen (O) atoms.
2. The subscript number indicates the number of atoms for each element. In this case, the subscripts are 2 for Na, 1 for H, 1 for P, and 4 for O.
3. Multiply the subscript by the number of atoms for each element:
- Na: 2 atoms x 2 subscripts = 4 atoms
- H: 1 atom x 1 subscript = 1 atom
- P: 1 atom x 1 subscript = 1 atom
- O: 4 atoms x 4 subscripts = 16 atoms
Therefore, the formula Na2HPO4 contains a total of 4 + 1 + 1 + 16 = 22 atoms.
To determine the number of atoms represented in the formula Na2HPO4, we need to analyze the chemical formula and count the atoms of each element present.
In Na2HPO4, Na represents sodium, H represents hydrogen, P represents phosphorus, and O represents oxygen.
Let's break it down:
- Na2 means there are two sodium atoms.
- H represents one hydrogen atom.
- PO4 means there is one phosphorus atom and four oxygen atoms.
Therefore, the total number of atoms in Na2HPO4 is:
2 sodium atoms + 1 hydrogen atom + 1 phosphorus atom + 4 oxygen atoms = 2 + 1 + 1 + 4 = 8
So, there are 8 atoms represented in the formula Na2HPO4.