Find an equation of a circle that satisfies the given conditions.
Center (–2, –8), radius 10
The equation of a circle with center (h, k) and radius r is given by:
(x - h)^2 + (y - k)^2 = r^2
In this case, the center is (-2, -8) and the radius is 10, so the equation is:
(x - (-2))^2 + (y - (-8))^2 = 10^2
(x + 2)^2 + (y + 8)^2 = 100
To find the equation of a circle given the center and radius, we can use the standard form of the equation of a circle, which is:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) are the coordinates of the center of the circle, and r is the radius. In this case, the center is (-2, -8), and the radius is 10. Substituting these values into the equation, we get:
(x - (-2))^2 + (y - (-8))^2 = 10^2
Simplifying, we have:
(x + 2)^2 + (y + 8)^2 = 100
Therefore, the equation of the circle is (x + 2)^2 + (y + 8)^2 = 100.
To find the equation of a circle given its center and radius, we can use the standard form of the equation:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) represents the coordinates of the center and 'r' is the radius.
In this case, the center is (-2, -8) and the radius is 10. Plugging these values into the standard form, we get:
(x - (-2))^2 + (y - (-8))^2 = 10^2
Simplifying, we have:
(x + 2)^2 + (y + 8)^2 = 100
Therefore, the equation of the circle is (x + 2)^2 + (y + 8)^2 = 100.