Butyric acid has a density of 0.959 g/mL at 20°C. How many moles of butyric acid are contained in 1.56 mL of butyric acid Expresp your answer to three significant figures and include the appropriate units.

To find the number of moles of butyric acid, we need to use the formula:

moles = mass / molar mass

First, we need to find the mass of butyric acid in 1.56 mL. We can do this by multiplying the volume (1.56 mL) by the density (0.959 g/mL):

mass = volume * density
mass = 1.56 mL * 0.959 g/mL
mass = 1.49504 g

Next, we need to calculate the molar mass of butyric acid. The molecular formula of butyric acid is C₄H₈O₂. To calculate the molar mass, we can sum the atomic masses of each element in the formula:

molar mass = (4 * atomic mass of carbon) + (8 * atomic mass of hydrogen) + (2 * atomic mass of oxygen)
molar mass = (4 * 12.01 g/mol) + (8 * 1.008 g/mol) + (2 * 16.00 g/mol)
molar mass = 88.11 g/mol

Now we can determine the number of moles of butyric acid by dividing the mass (1.49504 g) by the molar mass (88.11 g/mol):

moles = mass / molar mass
moles = 1.49504 g / 88.11 g/mol
moles = 0.01695 mol

Therefore, there are 0.017 mol of butyric acid in 1.56 mL.

To solve this problem, we need to use the equation:

moles = mass / molar mass

First, we need to calculate the mass of butyric acid in 1.56 mL using the density provided. The equation for mass is:

mass = density * volume

mass = 0.959 g/mL * 1.56 mL

mass = 1.49604 g

Next, we need to determine the molar mass of butyric acid, which is C4H8O2. To calculate the molar mass, we need to add up the atomic masses of carbon (C), hydrogen (H), and oxygen (O):

C: Atomic mass = 12.01 g/mol
H: Atomic mass = 1.01 g/mol
O: Atomic mass = 16.00 g/mol

Molar mass = (4 * 12.01 g/mol) + (8 * 1.01 g/mol) + (2 * 16.00 g/mol)
Molar mass = 88.11 g/mol

Now we can calculate the number of moles:

moles = mass / molar mass
moles = 1.49604 g / 88.11 g/mol

moles ≈ 0.017 (rounded to three significant figures)

Therefore, there are approximately 0.017 moles of butyric acid in 1.56 mL of butyric acid.

To find the number of moles of butyric acid contained in 1.56 mL, we need to use the given density and the molar mass of butyric acid.

Step 1: Calculate the mass of butyric acid in grams.
Mass (g) = Density (g/mL) x Volume (mL)
Mass (g) = 0.959 g/mL x 1.56 mL

Step 2: Convert grams to moles using the molar mass of butyric acid.
To do this, we need to know the molar mass of butyric acid, which is the sum of the atomic masses of all the atoms in the compound.

The molecular formula of butyric acid is C4H8O2.
The atomic mass of carbon (C) is 12.01 g/mol.
The atomic mass of hydrogen (H) is 1.01 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.

Molar mass of butyric acid = (4 x Atomic mass of C) + (8 x Atomic mass of H) + (2 x Atomic mass of O)
Molar mass of butyric acid = (4 x 12.01 g/mol) + (8 x 1.01 g/mol) + (2 x 16.00 g/mol)

Step 3: Calculate the number of moles.
Number of moles = Mass (g) / Molar mass (g/mol)

Plug in the values:
Number of moles = (0.959 g/mL x 1.56 mL) / Molar mass (g/mol)

Now you can calculate the number of moles of butyric acid contained in 1.56 mL using the given information about density and the molar mass of butyric acid.