Three cells are connected as shown. The internal resistance of each cell is 2 ohms. The voltage of each cell is 1.5 volts. The resistance of the external circuit is 2.3 ohms. What is the circuit current to the nearest tenth ampere?
To find the circuit current, we can use Ohm's Law, which states that the current flowing through a circuit is equal to the voltage divided by the resistance.
First, we need to find the total internal resistance of the three cells. Since each cell has an internal resistance of 2 ohms, the total internal resistance is 2 ohms + 2 ohms + 2 ohms = 6 ohms.
Next, we can find the total resistance of the circuit by adding the external resistance to the total internal resistance. Therefore, the total resistance is 6 ohms + 2.3 ohms = 8.3 ohms.
Now, we can use Ohm's Law to find the circuit current. The voltage provided by the three cells is 1.5 volts each, so the total voltage provided is 1.5 volts + 1.5 volts + 1.5 volts = 4.5 volts.
Therefore, the circuit current is 4.5 volts / 8.3 ohms = 0.5 amperes.
So, the circuit current is approximately 0.5 amperes to the nearest tenth.
To find the circuit current, we can use Ohm's Law, which states that current (I) is equal to voltage (V) divided by resistance (R).
1. First, let's find the total internal resistance of the cells connected in series. Since each cell has an internal resistance of 2 ohms, and there are three cells connected in series, the total internal resistance is 2 ohms multiplied by 3, which equals 6 ohms.
2. Next, let's find the total resistance of the circuit. The external resistance is given as 2.3 ohms, and we need to add the total internal resistance of 6 ohms to it. Therefore, the total resistance of the circuit is 2.3 ohms + 6 ohms, which equals 8.3 ohms.
3. Now, we can find the circuit current by using Ohm's Law. The voltage of each cell is 1.5 volts, so the total voltage across the circuit is 1.5 volts multiplied by 3 cells, which equals 4.5 volts.
Using Ohm's Law, I = V / R, we can calculate the circuit current.
I = 4.5 volts / 8.3 ohms
I ≈ 0.542 ampere
Therefore, the circuit current, to the nearest tenth ampere, is approximately 0.5 ampere.
To find the circuit current, we can use Ohm's Law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the total resistance (R).
In this case, the voltage of each cell is 1.5 volts, so the total voltage (V) is 1.5 volts multiplied by 3 cells, which gives us a total voltage of 4.5 volts.
The total resistance (R) is the sum of the internal resistance of each cell and the resistance of the external circuit. Therefore, the total resistance is 2 ohms (internal resistance per cell) multiplied by 3 cells, plus 2.3 ohms (external resistance), which gives us a total resistance of 8.3 ohms.
Now, we can use Ohm's Law to calculate the circuit current.
I = V / R
I = 4.5 V / 8.3 Ω
Calculating this, we find that the circuit current is approximately 0.542 amperes (rounded to the nearest tenth).