A chemist took several small beakers of solution and combined them in a large pitcher. He poured in 696.484 milliliters from the first beaker, 936.54 milliliters from the next beaker, 588.31 milliliters from the third beaker, 981.6 milliliters from the fourth beaker, and 732.988 milliliters from the last beaker. How many milliliters of the solution did the chemist put in the pitcher?
The chemist poured a total of 696.484 mL + 936.54 mL + 588.31 mL + 981.6 mL + 732.988 mL = <<696.484+936.54+588.31+981.6+732.988=3935.922>>3935.922 milliliters of solution in the pitcher. Answer: \boxed{3935.922}.
To find the total amount of solution in the pitcher, we need to add up the amounts poured from each beaker.
First, we add the volumes poured from the first and second beakers:
696.484 + 936.54 = 1633.024 milliliters.
Next, we add the volume poured from the third beaker to the previous total:
1633.024 + 588.31 = 2221.334 milliliters.
Then, we add the volume poured from the fourth beaker to the new total:
2221.334 + 981.6 = 3202.934 milliliters.
Finally, we add the volume poured from the last beaker to the previous total:
3202.934 + 732.988 = 3935.922 milliliters.
Therefore, the chemist put 3935.922 milliliters of solution in the pitcher.
To find the total number of milliliters of the solution the chemist put in the pitcher, you need to add up the volumes of the solution from each beaker.
Adding the volumes from each beaker:
696.484 mL + 936.54 mL + 588.31 mL + 981.6 mL + 732.988 mL
Now, let's add these numbers together:
696.484 + 936.54 + 588.31 + 981.6 + 732.988 = 3935.922 mL
Therefore, the chemist put 3935.922 milliliters of the solution in the pitcher.