A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 98 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell? 33 Skip to navigation
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A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. (4 points) a) An equation for the total cars and trucks for Dealership A: x + y = 225 b) An equation for the total cars and trucks for Dealership B: 2x + 1/2y = 300 c) How many cars did Dealership A sell? 98 d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
We can set up a system of equations to solve for the number of cars and trucks sold by each dealership.
Let's let x represent the number of cars sold and y represent the number of trucks sold.
From the information given, we know that for Dealership A:
x + y = 225
For Dealership B, it is stated that it sells twice as many cars and half as many trucks as Dealership A, so:
2x + (1/2)y = 300
Now we can solve for the values of x and y.
a) To find the number of cars sold by Dealership A, we can substitute the value of y from equation (1) into equation (2) and solve for x:
x + y = 225
x + (225 - x) = 225
x + 225 - x = 225
225 = 225
So, the equation x = 225 is true for any value of x. This means that the number of cars sold by Dealership A can be any number as long as the number of trucks sold is (225 - x).
c) Knowing that x can be any number, we cannot determine the exact number of cars sold by Dealership A without additional information.
d) However, we can use the information given in part d to solve for the number of trucks sold by Dealership B. It is stated that Dealership B sold half as many trucks as Dealership A.
So, the number of trucks sold by Dealership B is (1/2)(225 - x).
Since the total number of cars and trucks sold by Dealership B is 300:
2x + (1/2)(225 - x) = 300
2x + (225/2) - (1/2)x = 300
(3/2)x + (225/2) = 300
(3/2)x = 300 - (225/2)
(3/2)x = 300 - 112.5
(3/2)x = 187.5
x = (2/3)(187.5)
x = 125
Substituting this value back into the equation for Dealership A, we can find the number of trucks sold by Dealership B:
y = 225 - x
y = 225 - 125
y = 100
Therefore, Dealership B sold 125 cars and 100 trucks.