Subtract (3b-2c)-(6c+2b)-(b+c)

To subtract (3b-2c)-(6c+2b)-(b+c), you will need to combine like terms and simplify the expression.

First, distribute the negative sign to each term within the parentheses:
(3b-2c) - (6c+2b) - (b+c) = 3b - 2c - 6c - 2b - b - c

Next, combine like terms:
(3b - 2b) + (-2c - 6c - c) = b - 9c

Therefore, the simplified expression is b - 9c.

To subtract (3b - 2c) - (6c + 2b) - (b + c), we need to simplify each expression within the parentheses and then combine like terms.

First, let's simplify each expression:
(3b - 2c) becomes 3b - 2c
(6c + 2b) becomes 6c + 2b
(b + c) becomes b + c

Now, let's subtract the expressions:
(3b - 2c) - (6c + 2b) - (b + c) = 3b - 2c - 6c - 2b - b - c

Next, let's combine like terms:
Combine 'b' terms: 3b - 2b - b = 0b (since 3b - 2b - b = 0b)
Combine 'c' terms: -2c - 6c - c = -9c (since -2c - 6c - c = -9c)

Therefore, the final expression is:
3b - 2c - 6c - 2b - b - c simplifies to -9c.

To subtract the given expression, (3b-2c)-(6c+2b)-(b+c), let's simplify it step by step:

Step 1: Distribute the negative sign through the parentheses.
- (3b-2c) - (6c+2b) - (b+c)
= -3b + 2c -6c -2b - b - c

Step 2: Combine like terms. Group terms with the same variables together.
= (-3b - 2b - b) + (2c - 6c - c)
= -6b - 5c - 7c
= -6b - 12c

Therefore, the simplified expression is -6b - 12c.

IS THIS TRUE?

is this right?