Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box with a force of 50 N. The box exerts a frictional force of 65 N.

Which best explains the forces?

There is a net force of 15 N against them and they cannot move the box.
There is a net force of 15 N allowing Levi and Clara to move the box.
There is a net force of 65 N against them and they cannot move the box.
There is a net force of 80 N allowing Levi and Clara to move the box.

The correct answer is: There is a net force of 15 N against them and they cannot move the box.

To determine the net force, we need to sum up all the forces acting on the box. In this case, the force Levi is pushing with is 30 N, the force Clara is pulling with is 50 N, and the frictional force is 65 N.

To calculate the net force, we add up the forces in the direction of motion (assuming they both push/pull in the same direction) and subtract the force opposing motion (the frictional force).

Net force = (30 N + 50 N) - 65 N = 80 N - 65 N = 15 N

Since the net force is 15 N (against them), it means that there is still a force opposing motion (due to friction) that is greater than the force they are applying. Therefore, they cannot move the box.

To determine the net force acting on Levi and Clara and whether they can move the box, we need to calculate the net force by considering the forces involved. The net force is the vector sum of all the forces acting on an object.

In this scenario, there are two forces working in the same direction (Levi's pushing force and Clara's pulling force) and one force working in the opposite direction (the frictional force exerted by the box). To calculate the net force, we need to subtract the force of friction from the combined force of Levi and Clara.

Net force = (Force of pushing by Levi + Force of pulling by Clara) - Force of friction

Net force = (30 N + 50 N) - 65 N
= 80 N - 65 N
= 15 N

The net force acting on Levi and Clara is 15 N.

Now, based on the magnitude of the net force, we can determine if Levi and Clara can move the box. Newton's first law of motion states that an object at rest or in motion will remain in that state unless acted upon by an external force. Therefore, if the net force is non-zero (not equal to 0 N), there will be an acceleration, allowing Levi and Clara to move the box.

From the given options, the correct answer is:
There is a net force of 15 N allowing Levi and Clara to move the box.

To determine the net force, we need to subtract the opposing force of friction from the combined applied forces.

The force exerted by Levi is 30 N, the force exerted by Clara is 50 N, and the frictional force is 65 N.

To find the net force, we need to subtract the frictional force from the combined applied forces:
Net force = (Force applied by Levi + Force applied by Clara) - Frictional force
Net force = (30 N + 50 N) - 65 N
Net force = 80 N - 65 N
Net force = 15 N

Therefore, the correct answer is: There is a net force of 15 N allowing Levi and Clara to move the box.

yay another 80 percent in the test TY!!

You're welcome! I'm glad I could assist you and that you did well on your test. If you have any more questions, feel free to ask. Keep up the good work!

omg are u serious ANOTHER ONE?!? I did like 3...

_______________ is the displacement of an object during a specific unit of time.

The displacement of an object during a specific unit of time is called velocity.

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. His car was 20 meters from the starting line. This took 5 seconds.

What is the car’s average velocity?

4 m/s east
4 m/s west
12 m/s west
12 m/s east

To determine the car's average velocity, we need to calculate the total displacement and divide it by the total time taken.

The total displacement is the final position minus the initial position. In this case, the car started at the starting line (0 meters) and ended up 20 meters west.

Total displacement = Final position - Initial position
= -20 meters

The total time taken is given as 5 seconds.

Average velocity = Total displacement / Total time taken
= (-20 meters) / (5 seconds)
= -4 meters/second

The negative sign indicates that the car is moving west, opposite to the chosen positive direction (east).

Therefore, the car's average velocity is 4 m/s west.

An object has a mass of 5 kg. What force is needed to accelerate it at 6 m/s2? (Formula: F=ma)

0.83 N
1.2 N
11 N
30 N