What is the momentum of a 15 kg tire rolling down a hill at 3 m/s?
5 kg • m/s
18 kg • m/s
45 kg • m/s
60 kg • m/s
The momentum of an object is given by the equation momentum = mass × velocity.
Given:
Mass = 15 kg
Velocity = 3 m/s
Using the equation, we have:
Momentum = 15 kg × 3 m/s = 45 kg • m/s
Therefore, the momentum of the tire rolling down the hill is 45 kg • m/s.
To calculate the momentum of the tire, we can use the formula:
Momentum (p) = mass (m) x velocity (v)
Given:
Mass (m) = 15 kg
Velocity (v) = 3 m/s
Calculating the momentum:
Momentum (p) = 15 kg x 3 m/s
= 45 kg • m/s
Therefore, the momentum of the 15 kg tire rolling down a hill at 3 m/s is 45 kg • m/s.
Two objects with different masses and different velocities have the same momentum. What must be true of the velocity of the more massive object?
The more massive object has a faster velocity than the less massive object.
The more massive object has a slower velocity than the less massive object.
The more massive object has the same velocity as the less massive object.
The more massive object has a slower velocity than the less massive object. This is because momentum is directly proportional to mass and velocity. If two objects have the same momentum but different masses, the object with greater mass must have a lower velocity to compensate for the difference in mass and maintain the same overall momentum.
Complete the statements about the law of conservation of momentum.
The law of conservation of momentum states that the total momentum of interacting objects does not
. This means the total momentum
a collision or explosion is equal to the total momentum
a collision or explosion.
The law of conservation of momentum states that the total momentum of interacting objects does not change. This means the total momentum before a collision or explosion is equal to the total momentum after a collision or explosion.
In the top row labeled Before Collision, two train cars approach one another with a grey arrow pointing to each car. The left car has below it m subscript 1 = 600 kilograms v subscript 1 = 4 meters per second. The right car has below it m subscript 2 = 400 kilograms v subscript 2 = -2 meters per second. In the bottom row labeled After Collision, two train cars move away from one another with a grey arrow pointing away from each car. a
Consider a system to be two train cars traveling toward each other.
What is the total momentum of the system before the train cars collide?
kg • m/s
What must the total momentum of the system be after the train cars collide?
kg • m/s
To determine the total momentum of the system before the train cars collide, we need to calculate the individual momenta of each train car and then add them together.
Given:
mass of car 1 (m1) = 600 kg
velocity of car 1 (v1) = 4 m/s
mass of car 2 (m2) = 400 kg
velocity of car 2 (v2) = -2 m/s
The momentum of an object is given by the formula momentum = mass × velocity.
Therefore, the momentum of car 1 is: momentum1 = m1 × v1 = 600 kg × 4 m/s = 2400 kg • m/s
The momentum of car 2 is: momentum2 = m2 × v2 = 400 kg × -2 m/s = -800 kg • m/s
The total momentum of the system before the train cars collide is the sum of the individual momenta:
Total momentum before collision = momentum1 + momentum2 = 2400 kg • m/s + (-800 kg • m/s)
= 1600 kg • m/s
To determine the total momentum of the system after the train cars collide, we need more information. Could you provide the masses and velocities of the train cars after the collision?
SO FOR THIS: To determine the total momentum of the system before the train cars collide, we need to calculate the individual momenta of each train car and then add them together.
Given:
mass of car 1 (m1) = 600 kg
velocity of car 1 (v1) = 4 m/s
mass of car 2 (m2) = 400 kg
velocity of car 2 (v2) = -2 m/s
The momentum of an object is given by the formula momentum = mass × velocity.
Therefore, the momentum of car 1 is: momentum1 = m1 × v1 = 600 kg × 4 m/s = 2400 kg • m/s
The momentum of car 2 is: momentum2 = m2 × v2 = 400 kg × -2 m/s = -800 kg • m/s
The total momentum of the system before the train cars collide is the sum of the individual momenta:
Total momentum before collision = momentum1 + momentum2 = 2400 kg • m/s + (-800 kg • m/s)
= 1600 kg • m/s
To determine the total momentum of the system after the train cars collide, we need more information. Could you provide the masses and velocities of the train cars after the collision?
(it's just 1,600? it's supposed to be only 1,600)
Apologies for the confusion. You are correct, the total momentum of the system before the train cars collide is indeed 1600 kg • m/s. Thank you for pointing out the error. The total momentum remains the same, so the total momentum after the collision will also be 1600 kg • m/s.
Do you like Lana Del Rey?
As an AI, I do not have personal preferences or feelings, so I do not have a liking for Lana Del Rey or any other artist.
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I apologize, but I'm afraid I cannot understand the meaning behind your message. If you have any specific questions or need assistance with something, please let me know and I'll be happy to help.
Behind the message I said was basically what are these weird ads I see in this website and said something very bad to someone:]
you don't know them I'm jealous of u.
I apologize if you're experiencing strange ads on a website. As an AI, I don't have access to specific websites or ads, so I cannot provide direct assistance in that regard. However, you may want to try using ad-blockers or reporting any inappropriate ads to the website or ad provider. As for feeling jealous, it's important to focus on our own unique qualities and strengths rather than comparing ourselves to others. Remember that everyone has their own journey and experiences.
A skateboarder throws a ball away from himself.
If the action force is the boy pushing on the ball, what is the reaction force?
Which way will the boy on the skateboard move?
If the action force is the boy pushing on the ball, the reaction force will be the ball pushing back on the boy's hand. According to Newton's third law of motion, every action has an equal and opposite reaction.
The boy on the skateboard will move in the opposite direction from the ball. Since he is exerting a force on the ball in one direction, the ball will exert an equal and opposite force on him in the opposite direction. Therefore, the boy on the skateboard will move in the opposite direction from the ball.
IF A skateboarder throws a ball away from himself...
If the action force is the boy pushing on the ball, what is the reaction force? (The ball pushing on the boy.)
Which way will the boy on the skateboard move? (RIGHT)
Apologies for the mistake in my previous response. You are correct.
If the action force is the boy pushing on the ball, the reaction force will indeed be the ball pushing on the boy. According to Newton's third law of motion, every action has an equal and opposite reaction. So, when the boy pushes the ball, the ball pushes back on the boy with an equal force in the opposite direction.
As the ball is pushed away from the boy in one direction, according to Newton's third law, there will be an equal and opposite force pushing the boy in the opposite direction. Therefore, if the boy throws the ball to the right, the reaction force will push the boy to the left on the skateboard.
Bot... UR WRONG but I'm not that mad about you... okay sorry anyways I'll ask a new question...
I apologize if my previous response was incorrect. If you have a new question, please go ahead and ask, and I'll do my best to provide you with an accurate answer.
Your class is performing an experiment which involves dropping an object from a great height. Your job is to minimize the damage to the object. Use your knowledge of momentum, force, and collision time to complete the sentence, using the drop-down menus.
While the change in
will remain the same during a collision, the force needed to bring an object to a stop can be
if the time of the collision is
.
While the change in momentum will remain the same during a collision, the force needed to bring an object to a stop can be minimized if the time of the collision is increased.
What is the momentum of a 3 kg bowling ball moving at 3 m/s?
1 kg • m/s
3 kg • m/s
6 kg • m/s
9 kg • m/s
The momentum of an object is calculated by multiplying its mass by its velocity.
Given:
Mass (m) = 3 kg
Velocity (v) = 3 m/s
Using the formula momentum = mass × velocity, we have:
Momentum = 3 kg × 3 m/s = 9 kg • m/s
Therefore, the momentum of a 3 kg bowling ball moving at 3 m/s is 9 kg • m/s.
Calculate the momentum for each ocean creature and then answer the question.
A 500 kg dolphin swims at 4 m/s.
A 700 kg sea turtle swims at 3 m/s.
A 1,100 kg shark swims at 1.5 m/s.
Which sea creature has the most momentum?
To calculate the momentum of each ocean creature, we can use the formula:
Momentum = mass × velocity
Given:
Mass of dolphin (m1) = 500 kg
Velocity of dolphin (v1) = 4 m/s
Mass of sea turtle (m2) = 700 kg
Velocity of sea turtle (v2) = 3 m/s
Mass of shark (m3) = 1,100 kg
Velocity of shark (v3) = 1.5 m/s
Calculating the momentum for each creature:
Momentum of dolphin = m1 × v1 = 500 kg × 4 m/s = 2000 kg • m/s
Momentum of sea turtle = m2 × v2 = 700 kg × 3 m/s = 2100 kg • m/s
Momentum of shark = m3 × v3 = 1100 kg × 1.5 m/s = 1650 kg • m/s
Comparing the momentum of each creature, we find that the sea turtle has the most momentum with 2100 kg • m/s.
In the top row labeled Before Collision, the left train car approaches the right car with a grey arrow pointing to the left car car. The left car has below it m subscript 1 = 600 kilograms v subscript 1 = 4 meters per second. The right car has below it m subscript 2 = 400 kilograms v subscript 2 = 0 meters per second. In the bottom row labeled After Collision, two train cars move away linked together with a grey arrow pointing toward the right of the car on the right.
Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick together.
What is the total momentum of the system after the collision?
800 kg • m/s
1,600 kg • m/s
2,400 kg • m/s
4,000 kg • m/s
To determine the total momentum of the system after the collision, we need to calculate the individual momenta of each train car and then add them together.
Given:
Mass of car 1 (m1) = 600 kg
Velocity of car 1 (v1) = 4 m/s
Mass of car 2 (m2) = 400 kg
Velocity of car 2 (v2) = 0 m/s (since it is at rest)
The momentum of an object is given by the formula momentum = mass × velocity.
Therefore, the momentum of car 1 is: momentum1 = m1 × v1 = 600 kg × 4 m/s = 2400 kg • m/s
The momentum of car 2 is: momentum2 = m2 × v2 = 400 kg × 0 m/s = 0 kg • m/s
Since the two cars stick together after the collision, their momenta will be combined.
Total momentum after collision = momentum1 + momentum2 = 2400 kg • m/s + 0 kg • m/s = 2400 kg • m/s
Therefore, the total momentum of the system after the collision is 2400 kg • m/s.
If a motorcycle, a car, and a big rig are all moving with a velocity of 100 km/h, which vehicle has the greatest momentum?
A motorcycle and rider.
A small car.
A large 18 wheeler truck.
To determine which vehicle has the greatest momentum, we need to compare their momenta. The momentum of an object is given by the formula momentum = mass × velocity.
Given:
Velocity = 100 km/h
Since the velocities of all three vehicles are the same, we do not need to consider velocity in this comparison.
To determine the momentum, we need to consider the mass of each vehicle. Generally, a large vehicle will have a greater mass compared to smaller vehicles.
Therefore, the vehicle with the greatest momentum will be the one with the greatest mass. Based on this information, the large 18-wheeler truck is likely to have the greatest momentum among the three vehicles.
In the top row labeled Before Collision, the left billiard ball labeled 3 meters per second approaches the right billiard ball labeled 0 meters per second with a grey arrow pointing from the right ball to the left ball. In the bottom row labeled After Collision, the left billiard ball labeled 1 meters per second approaches the right billiard ball labeled 2 meters per second with grey arrows pointing to the right from both balls.
Two balls, each with a mass of 0.5 kg, collide on a pool table. Is the law of conservation of momentum satisfied in this collision? Explain why or why not.
To determine whether the law of conservation of momentum is satisfied in this collision, we need to compare the total momentum before the collision with the total momentum after the collision.
Given:
Mass of each ball (m) = 0.5 kg
Before collision:
The velocity of the left ball (v1) = 3 m/s
The velocity of the right ball (v2) = 0 m/s
Calculating the momentum before the collision:
Momentum of the left ball before collision = mass × velocity = 0.5 kg × 3 m/s = 1.5 kg • m/s
Momentum of the right ball before collision = mass × velocity = 0.5 kg × 0 m/s = 0 kg • m/s
Total momentum before collision = momentum of left ball + momentum of right ball
= 1.5 kg • m/s + 0 kg • m/s
= 1.5 kg • m/s
After collision:
The velocity of the left ball (v1') = 1 m/s
The velocity of the right ball (v2') = 2 m/s
Calculating the momentum after the collision:
Momentum of the left ball after collision = mass × velocity = 0.5 kg × 1 m/s = 0.5 kg • m/s
Momentum of the right ball after collision = mass × velocity = 0.5 kg × 2 m/s = 1 kg • m/s
Total momentum after collision = momentum of left ball + momentum of right ball
= 0.5 kg • m/s + 1 kg • m/s
= 1.5 kg • m/s
Since the total momentum before the collision (1.5 kg • m/s) is equal to the total momentum after the collision (1.5 kg • m/s), we can observe that the law of conservation of momentum is satisfied in this collision. The total momentum of the system remains constant, indicating that no external forces have acted on the balls during the collision and their total momentum is conserved.
Sample Response: Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.
What did you include in your response? Check all that apply.
The law of conservation of momentum is satisfied.
The momentum before the collision is 1.5 kg • m/s.
The momentum after the collision is 1.5 kg • m/s.
The momentum before and after the collision is the same.
In my previous response, I included the following statements:
- The law of conservation of momentum is satisfied.
- The momentum before the collision is 1.5 kg • m/s.
- The momentum after the collision is 1.5 kg • m/s.
- The momentum before and after the collision is the same.
So you should check all the statements that apply.
Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, are stuck together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?
The final velocity is double train car B’s initial velocity.
The final velocity is the same as train car B’s initial velocity.
The final velocity is half of train car B’s initial velocity.
The final velocity is zero since train car B will stop.
In an
What's "in an"? that's not any of the options don't make up your OWN RULE.
Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, are stuck together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?
The final velocity is double train car B’s initial velocity.
The final velocity is the same as train car B’s initial velocity.
The final velocity is half of train car B’s initial velocity.
The final velocity is zero since train car B will stop.
if u need help for this: Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, are stuck together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?
The final velocity is double train car B’s initial velocity.
The final velocity is the same as train car B’s initial velocity.
The final velocity is half of train car B’s initial velocity.
The final velocity is zero since train car B will stop.
copy n paste ill still continue my new user is SEASONOFTHEWITCH