What is the distance between the following points?
(2, -3) (8, -9)
To find the distance between two points, you can use the distance formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the points are (2, -3) and (8, -9). Let's plug these values into the formula:
d = √((8 - 2)^2 + (-9 - (-3))^2)
= √((6)^2 + (-6)^2)
= √(36 + 36)
= √72
≈ 8.485
Therefore, the distance between the points (2, -3) and (8, -9) is approximately 8.485 units.
To find the distance between two points (x1, y1) and (x2, y2), you can use the distance formula:
Distance = √((x₂ - x₁)² + (y₂ - y₁)²)
Using the given points (2, -3) and (8, -9), we can substitute the values into the formula:
Distance = √((8 - 2)² + (-9 - (-3))²)
Distance = √((6)² + (-6)²)
Distance = √(36 + 36)
Distance = √72
To simplify the square root, we can rewrite 72 as the product of a perfect square and a non-perfect square. Since 36 is a perfect square, we can write:
Distance = √(36 * 2)
Distance = √36 * √2
Distance = 6√2
Therefore, the distance between the points (2, -3) and (8, -9) is 6√2 or approximately 8.49 units.
What is the distance between the following points?
(2, -3) (8, -9)
The distance between the points (2, -3) and (8, -9) can be calculated using the distance formula:
Distance = √((x₂ - x₁)² + (y₂ - y₁)²)
Plugging in the given values:
Distance = √((8 - 2)² + (-9 - (-3))²)
Distance = √(6² + (-6)²)
Distance = √(36 + 36)
Distance = √72
To simplify the square root, we can rewrite 72 as the product of a perfect square and a non-perfect square. Since 36 is a perfect square, we can write:
Distance = √(36 * 2)
Distance = √36 * √2
Distance = 6√2
Therefore, the distance between the points (2, -3) and (8, -9) is 6√2 or approximately 8.49 units.
To find the distance between two points in a two-dimensional plane, we can use the distance formula. The formula is derived from the Pythagorean theorem.
The distance (d) between two points (x1, y1) and (x2, y2) can be calculated using the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Let's use this formula to find the distance between the points (2, -3) and (8, -9).
Step 1: Identify the coordinates
(x1, y1) = (2, -3)
(x2, y2) = (8, -9)
Step 2: Plug the values into the distance formula
d = sqrt((8 - 2)^2 + (-9 - (-3))^2)
Simplifying further:
d = sqrt(6^2 + (-6)^2)
d = sqrt(36 + 36)
d = sqrt(72)
Step 3: Calculate the square root
Using a calculator or estimation method, we find that sqrt(72) is approximately 8.485.
Therefore, the distance between the points (2, -3) and (8, -9) is approximately 8.485 units.