A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats are occupied. Find the percent error of Layla’s prediction. Round your answer to the nearest hundredth of a percent.(1 point)
Responses
−3.07%
negative 3.07 percent
0.0307%
0.0307%
3.07%
3.07%
90.3067%
To find the percent error, we need to compare the difference between the predicted value and the actual value to the actual value itself.
The actual value is 81,500 seats and the predicted value is 79,000 seats.
The difference between the predicted value and the actual value is 81,500 - 79,000 = 2,500.
To find the percent error, we divide the difference by the actual value and multiply by 100:
(2,500 / 81,500) * 100 = 0.0307 * 100 = 3.07%
So the percent error of Layla's prediction is 3.07%.
To find the percent error of Layla's prediction, we need to compare her predicted number of occupied seats (79,000) with the actual number of occupied seats (81,500).
The formula for percent error is:
Percent Error = (|Predicted Value - Actual Value| / Actual Value) * 100
Substituting the given values:
Percent Error = (|79,000 - 81,500| / 81,500) * 100
Calculating:
Percent Error ≈ (2,500 / 81,500) * 100 ≈ 0.0307 (rounded to 4 decimal places)
Therefore, the percent error of Layla's prediction is approximately 0.0307%, which is equivalent to 0.03% when rounded to the nearest hundredth of a percent.
To find the percent error of Layla's prediction, we will use the formula:
Percent Error = [(Observed value - Expected value) / Expected value] * 100
In this case, the observed value is 79,000 seats (Layla's prediction) and the expected value is 81,500 seats (full capacity of the stadium).
Substituting these values into the formula:
Percent Error = [(79,000 - 81,500) / 81,500] * 100
Percent Error = (-2,500 / 81,500) * 100
Percent Error ≈ -3.07%
Therefore, the percent error of Layla's prediction is approximately -3.07%.