The point (0,-2) is a solution to which system?
(1 point)
A. -4x + y = 6
-5x -y= 21
B. x + y = 2
-x + 2y = 16
C. -5x +y= -2
-3x + 6y = -12
D. -5x =y - 3
3x - 8y = 24
To determine which system the point (0,-2) is a solution to, we can substitute the values of x and y into each equation and check if the equations are satisfied.
Let's substitute the values into each system:
A. -4x + y = 6
Substituting (0,-2):
-4(0) + (-2) = 6
0 - 2 = 6
-2 = 6
The equation is not satisfied, so (0,-2) is not a solution to system A.
B. x + y = 2
Substituting (0,-2):
0 + (-2) = 2
-2 = 2
Again, the equation is not satisfied, so (0,-2) is not a solution to system B.
C. -5x + y = -2
Substituting (0,-2):
-5(0) + (-2) = -2
0 - 2 = -2
-2 = -2
The equation is satisfied, so (0,-2) is a solution to system C.
D. -5x = y - 3
Substituting (0,-2):
-5(0) = (-2) - 3
0 = -2 - 3
0 = -5
The equation is not satisfied, so (0,-2) is not a solution to system D.
Therefore, the point (0,-2) is a solution to system C.
To determine which system the point (0,-2) is a solution to, we can substitute the values of x and y from the point into each system and check which equation(s) are true.
Let's substitute the values x = 0 and y = -2 into each system:
A. -4(0) + (-2) = 6
0 - 2 = 6
-2 = 6
The equation is not true, so (0, -2) is not a solution to System A.
B. (0) + (-2) = 2
-2 = 2
The equation is not true, so (0, -2) is not a solution to System B.
C. -5(0) + (-2) = -2
0 + (-2) = -2
-2 = -2
The equation is true, so (0, -2) is a solution to System C.
D. -5(0) = (-2) - 3
0 = -2 - 3
0 = -5
The equation is not true, so (0, -2) is not a solution to System D.
Therefore, the point (0, -2) is a solution to System C.
To determine which system has the point (0,-2) as a solution, we substitute the values x=0 and y=-2 into each equation of the system and see if it satisfies the equations.
A) -4x + y = 6; substituting x=0 and y=-2:
-4(0) + -2 = 6
0 - 2 = 6
-2 = 6 This equation is not satisfied, so the point (0,-2) is not a solution to system A.
B) x + y = 2; -x + 2y = 16; substituting x=0 and y=-2:
0 + -2 = 2 -0 + 2(-2) = 16
-2 = 2 -0 - 4 = 16
The first equation is not satisfied, so the point (0,-2) is not a solution to system B.
C) -5x +y= -2; -3x + 6y = -12; substituting x=0 and y=-2:
-5(0) + -2 = -2 -3(0) + 6(-2) = -12
0 - 2 = -2 0 - 12 = -12
The equations are satisfied, so the point (0,-2) is a solution to system C.
D) -5x =y - 3; 3x - 8y = 24; substituting x=0 and y=-2:
-5(0) = -2 - 3 3(0) - 8(-2) = 24
0 = -5 0 + 16 = 24
The first equation is not satisfied, so the point (0,-2) is not a solution to system D.
Therefore, the point (0,-2) is a solution to system C.