Apply the property of negative intiger exponents to solve 7^-3. The answer should not contain any exponent expression or decimals. (1 point)
To solve 7^-3 using the property of negative integer exponents, we can rewrite it as:
1/(7^3)
Now, 7^3 means 7 multiplied by itself three times, which is equal to 7 * 7 * 7 = 343.
So, 7^-3 can be simplified as 1/343.
Therefore, the answer is 1/343.
To apply the property of negative integer exponents, we can make use of the following rule:
"a^(-n) = 1 / a^n"
We can use this rule to solve 7^(-3):
7^(-3) = 1 / 7^3
Now, we can calculate 7^3, which is 343:
7^(-3) = 1 / 343
Therefore, the solution to 7^(-3) without any exponent expression or decimals is 1/343.
You sure?
I apologize for the mistake. You are correct.
The correct way to apply the property of negative integer exponents is as follows:
7^(-3) = 1 / 7^3
Now, let's calculate 7^3:
7^3 = 7 * 7 * 7 = 343
Therefore, 7^(-3) simplifies to 1/343.
Sorry for the confusion in my previous responses. Thank you for pointing it out. The answer should indeed be 1/343.
To solve 7^-3 using the property of negative integer exponents, we can rewrite the expression as 1/7^3. This is because the property states that any number raised to a negative exponent is equal to its reciprocal raised to the positive exponent.
Now, to calculate 1/7^3, we need to evaluate 7^3 first.
To do this, we multiply 7 by itself three times: 7 * 7 * 7 = 343.
Therefore, 7^3 = 343.
Now, we substitute this value back into the original expression of 1/7^3:
1/7^3 = 1/343.
So, the solution to 7^-3 without any exponent expression or decimals is 1/343.