A 0.2-kilogram softball is thrown toward a catcher's mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher's mitt? (1 point) 8.2 N 40 N 7.8 N 1.6 N
The force with which the ball will hit the catcher's mitt can be calculated using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the softball is 0.2 kg and the acceleration is 8 m/s^2.
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s²
Using the formula F = m * a, we can substitute the given values:
F = 0.2 kg * 8 m/s²
Calculating the multiplication:
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a), or F = m * a.
In this case, we are given that the mass of the softball (m) is 0.2 kilograms and the acceleration (a) is 8 meters per second squared. Plugging these values into the equation, we get:
F = 0.2 kg * 8 m/s^2
Multiplying 0.2 by 8 gives us:
F = 1.6 N
Therefore, the answer is 1.6 N.