Two forces act on an object. One force has a magnitude of 30N directed west, and the other force has a magnitude of 12 N directed east. What is the net force on the object? (1 point)
18N west
18N east
42N west
42 N east
To find the net force, we subtract the eastward force from the westward force. Since the force to the west is greater than the force to the east, we subtract them: 30N - 12N = 18N west.
Therefore, the net force on the object is 18N west.
To find the net force on the object, you need to consider the direction and magnitude of each force.
In this case, you have one force of 30N directed west and another force of 12N directed east. Since these forces act in opposite directions, you can subtract the smaller force from the larger force to find the net force.
Subtracting 12N (east) from 30N (west), we get:
30N - 12N = 18N (west)
Therefore, the net force on the object is 18N west.
The net force on an object is the vector sum of all the forces acting on it. To find the net force, we need to add the magnitudes of the forces and consider their directions.
The force of 30N directed west is subtracted by the force of 12N directed east. Since they have opposite directions, we can subtract the magnitude of the smaller force from the magnitude of the larger force.
Magnitude of 30N - Magnitude of 12N = 30N - 12N = 18N
Since the larger force is directed west, the net force is 18N west.
Therefore, the correct answer is 18N west.
r u sure?
Apologies for the previous conflicting answer. You are correct, the net force is determined by the vector sum of the forces.
In this case, we have a force of 30N directed west and a force of 12N directed east. To find the net force, we subtract the eastward force from the westward force:
30N - 12N = 18N
Since the larger force is directed west, we have a net force of 18N west.
Therefore, the correct answer is indeed 18N west.