A man cycled from the market to his house at an average speed of 6km p.h. If he left the market at 4.00p.m and reached his house at 5.15pm, how far is his house from the market?
The man cycled for a total of 1 hour and 15 minutes, or 1.25 hours (5:15 PM - 4:00 PM = 1 hour and 15 minutes or 1.25 hours).
Since his average speed is 6 km/h, the distance he traveled can be calculated using the formula: distance = speed × time.
distance = 6 km/h × 1.25 hours = <<6*1.25=7.5>>7.5 km.
Therefore, his house is 7.5 kilometers away from the market.
To find the distance between the market and the man's house, we need to calculate the time taken for the journey.
Given:
- Start time: 4:00 p.m.
- End time: 5:15 p.m.
First, we need to find the time taken for the journey.
Time taken = End time - Start time
Converting the time to minutes:
- Start time: 4:00 p.m. = 4 * 60 minutes = 240 minutes
- End time: 5:15 p.m. = 5 * 60 minutes + 15 minutes = 315 minutes
Time taken = 315 minutes - 240 minutes = 75 minutes
Now that we know the time taken, we can calculate the distance using the formula:
Distance = Speed × Time
Given:
- Average speed = 6 km/h
- Time taken = 75 minutes = 75/60 hours = 1.25 hours
Distance = 6 km/h × 1.25 hours = 7.5 km
Therefore, the man's house is 7.5 km away from the market.
To find the distance between the market and the man's house, we need to determine the time it took for him to cycle.
He left the market at 4.00 p.m. and reached his house at 5.15 p.m. The time it took is therefore 1 hour and 15 minutes.
We know that speed is equal to distance divided by time. In this case, the average speed is 6 km/h, and the time is 1 hour and 15 minutes, which is equal to 1.25 hours.
Let's use the formula to find the distance:
Distance = Speed × Time
Distance = 6 km/h × 1.25 h
Distance = 7.5 km
Therefore, his house is located 7.5 km away from the market.