The size of a hydrogen atom is about 1.2 × 10-10 m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation? (1 point)
0 3.2 × 10 ° m
O 2.72 × 10 10 m
0 3.2 × 10 10 m
O 3.2 × 10 11 m
The difference between the sizes of the atoms can be found by subtracting the size of the hydrogen atom from the size of the oxygen atom.
0.000000000152 m - 1.2 × 10^-10 m = 0.000000000152 m - 0.00000000012 m
Simplifying the decimal value gives:
0.000000000032 m
Converting this to scientific notation gives:
3.2 × 10^-11 m
Therefore, the correct answer is:
O 3.2 × 10^-11 m
To find the difference between the sizes of these atoms in scientific notation, we need to subtract the size of the hydrogen atom from the size of the oxygen atom.
The size of the hydrogen atom is 1.2 × 10^(-10) m and the size of the oxygen atom is 0.000000000152 m, which can be written as 1.52 × 10^(-10) m.
Subtracting the size of the hydrogen atom from the size of the oxygen atom gives us:
1.52 × 10^(-10) m - 1.2 × 10^(-10) m
To perform this subtraction, we subtract the numerical values and keep the same exponent:
(1.52 - 1.2) × 10^(-10) m
0.32 × 10^(-10) m
Finally, we can express this value in scientific notation by writing 0.32 as 3.2 × 10^(-1):
3.2 × 10^(-1) × 10^(-10) m
Adding the exponents, this can be simplified to:
3.2 × 10^(-1 - 10) m
3.2 × 10^(-11) m
Therefore, the difference between the sizes of these atoms in scientific notation is 3.2 × 10^(-11) m.
To find the difference between the sizes of these atoms in scientific notation, we need to subtract the size of the hydrogen atom from the size of the oxygen atom. Let's do the calculation.
The size of a hydrogen atom is given as 1.2 × 10^(-10) m.
The size of an oxygen atom is given as 0.000000000152 m, which can be written in scientific notation as 1.52 × 10^(-10) m.
To find the difference, we subtract the size of the hydrogen atom from the size of the oxygen atom:
1.52 × 10^(-10) m - 1.2 × 10^(-10) m
To subtract these values, we need to make sure the exponents are the same. Since both exponents are negative, we can directly subtract the decimal parts:
0.32 × 10^(-10) m
Finally, we write the result in scientific notation:
3.2 × 10^(-11) m
Therefore, the difference between the sizes of these atoms in scientific notation is 3.2 × 10^(-11) m. So the correct answer is: O) 3.2 × 10^(-11) m.