Mr. Brokaw class has 60 students, 1/4 of the students needed help for an upcoming test. If Mr. Brokaw equally divides the students that need help into 5 small groups, How many students are in each group
A 15
B 12
C 3
D 5
To solve this problem, you can start by finding out how many students need help for the upcoming test.
1/4 of the 60 students is (1/4) * 60 = 15 students.
Now, the problem states that these students are equally divided into 5 small groups. To find out how many students are in each group, you can divide the total number of students needing help (15) by the number of groups (5).
15 students ÷ 5 groups = 3 students
Therefore, there are 3 students in each group.
The answer is C) 3.
To find out how many students are in each group, we first need to determine how many students needed help for the test.
Given that 1/4 of the students needed help, we can calculate this by multiplying the total number of students by 1/4:
Number of students who needed help = 60 * 1/4
Number of students who needed help = 15
Since Mr. Brokaw wants to divide these students into 5 small groups, we can divide the total number of students who needed help by the number of groups:
Number of students in each group = 15 / 5
Number of students in each group = 3
Therefore, the correct answer is C) 3.
To find the number of students in each group, we need to determine how many students needed help for the upcoming test, and then divide that number by the number of small groups.
Given that there are 60 students in Mr. Brokaw's class and 1/4 of the students needed help, we can calculate the number of students who needed help by multiplying 60 by 1/4:
60 * 1/4 = 60/4 = 15
Therefore, 15 students needed help for the upcoming test.
Since Mr. Brokaw equally divides the students that need help into 5 small groups, we can calculate the number of students in each group by dividing the total number of students needing help (15) by the number of small groups (5):
15 / 5 = 3
Therefore, there are 3 students in each group.
Hence, the correct answer is option C: 3.