Select the ordered pairs that are solutions to the equation below.
2x + 3y = -12
Select all that apply
A. (0,-4)
B. (2,-1)
C. (0,0)
D. (-6,0)
To determine which ordered pairs are solutions to the equation 2x + 3y = -12, substitute the values of x and y into the equation and check if both sides are equal:
For option A: (0, -4)
2(0) + 3(-4) = 0 - 12 = -12.
This equation is true, so (0, -4) is a solution.
For option B: (2, -1)
2(2) + 3(-1) = 4 - 3 = 1.
This equation is not equal to -12, so (2, -1) is not a solution.
For option C: (0, 0)
2(0) + 3(0) = 0 + 0 = 0.
This equation is not equal to -12, so (0, 0) is not a solution.
For option D: (-6, 0)
2(-6) + 3(0) = -12 + 0 = -12.
This equation is true, so (-6, 0) is a solution.
Therefore, the ordered pairs that are solutions to the equation are A. (0, -4) and D. (-6, 0).
To find the ordered pairs that are solutions to the equation 2x + 3y = -12, we can substitute the values of x and y from each given option and check if the equation holds true. Let's go through each option:
A. (0, -4)
By substituting x = 0 and y = -4 into the equation:
2(0) + 3(-4) = 0 - 12 = -12 (equal to -12)
B. (2, -1)
By substituting x = 2 and y = -1 into the equation:
2(2) + 3(-1) = 4 - 3 = 1 (not equal to -12)
C. (0, 0)
By substituting x = 0 and y = 0 into the equation:
2(0) + 3(0) = 0 (not equal to -12)
D. (-6, 0)
By substituting x = -6 and y = 0 into the equation:
2(-6) + 3(0) = -12 (equal to -12)
So, the ordered pairs that are solutions to the equation are:
A. (0, -4)
D. (-6, 0)
To find the ordered pairs that are solutions to the equation, we need to substitute the values of x and y from each pair into the equation and see if it satisfies the equation.
Let's go through each option:
A. (0, -4)
Substituting x = 0 and y = -4 into the equation:
2(0) + 3(-4) = -12
0 - 12 = -12
-12 = -12
Since the equation is satisfied, option A is a solution.
B. (2, -1)
Substituting x = 2 and y = -1 into the equation:
2(2) + 3(-1) = -12
4 - 3 = -12
1 ≠ -12
Since the equation is not satisfied, option B is not a solution.
C. (0, 0)
Substituting x = 0 and y = 0 into the equation:
2(0) + 3(0) = -12
0 + 0 = -12
0 ≠ -12
Since the equation is not satisfied, option C is not a solution.
D. (-6, 0)
Substituting x = -6 and y = 0 into the equation:
2(-6) + 3(0) = -12
-12 + 0 = -12
-12 = -12
Since the equation is satisfied, option D is a solution.
Therefore, the ordered pairs that are solutions to the equation are A. (0, -4) and D. (-6, 0).