Write an equation of the line in standard form with integer coefficients.
y=1/5x -2
To write the equation in standard form with integer coefficients, we can multiply every term by 5 to eliminate the fraction:
5y = 1x - 10
Rearranging the terms:
x - 5y = 10
Thus, the equation in standard form with integer coefficients is x - 5y = 10.
To write the equation of a line in standard form with integer coefficients, we need to eliminate any fractions and ensure that the coefficients are integers.
Given the equation: y = (1/5)x - 2
To eliminate the fraction, we can multiply both sides of the equation by 5:
5y = 5 * [(1/5)x] - 5 * 2
5y = x - 10
Now we rearrange the equation to match the standard form, Ax + By = C, where A, B, and C are integers:
x - 5y = 10
Therefore, the equation of the line in standard form with integer coefficients is x - 5y = 10.
To write the equation in standard form with integer coefficients, we need to eliminate the fraction by multiplying every term by 5 to get rid of the denominator.
Multiplying both sides of the equation by 5, we have:
5y = 5 * (1/5)x - 5(2)
Simplifying, we get:
5y = x - 10
Moving all the terms to one side, the equation becomes:
x - 5y = 10
Thus, the equation in standard form with integer coefficients is:
x - 5y = 10