P1V1/T1=P2V2/T2 using this formula
V1=15L
V2=?
P1=4.8 atm
P2=17 atm
T1=298K
T2=348K
Using the formula P1V1/T1 = P2V2/T2, we can rearrange the equation to solve for V2:
V2 = V1 * P1 * T2 / (P2 * T1)
Plugging in the given values:
V2 = 15L * (4.8 atm) * (348K) / (17 atm * 298K)
Calculating further:
V2 = 15L * 4.8 atm * 348K / (17 atm * 298K)
V2 = 15L * 1658.4 / 5046
V2 = 4.939 L
Therefore, V2 is approximately 4.939 L.
To find the value of V2 in the equation P1V1/T1 = P2V2/T2, we can substitute the given values:
P1 = 4.8 atm,
V1 = 15 L,
T1 = 298 K,
P2 = 17 atm,
T2 = 348 K.
Now let's solve for V2:
P1V1/T1 = P2V2/T2
Substituting the values:
(4.8 atm)(15 L) / 298 K = (17 atm)(V2) / 348 K
To isolate V2, we can cross-multiply and solve for it:
(4.8 atm)(15 L)(348 K) = (17 atm)(V2)(298 K)
(4.8)(15)(348) = (17)(V2)(298)
Now, divide both sides of the equation by (17)(298):
(4.8 * 15 * 348) / (17 * 298) = V2
Calculating the value:
V2 ≈ 23.37 L
Therefore, the value of V2 is approximately 23.37 L.
To find the value of V2 using the formula P1V1/T1 = P2V2/T2, we can rearrange the formula to solve for V2.
The given values are:
V1 = 15 L
P1 = 4.8 atm
T1 = 298 K
P2 = 17 atm
T2 = 348 K
We can substitute these values into the formula:
P1V1/T1 = P2V2/T2
Let's plug in the values:
(4.8 atm * 15 L) / 298 K = (17 atm * V2) / 348 K
Now, let's solve for V2:
(4.8 atm * 15 L * 348 K) = (17 atm * V2 * 298 K)
Multiplying both sides:
(4.8 * 15 * 348) = (17 * V2 * 298)
V2 * 298 = (4.8 * 15 * 348) / 17
V2 * 298 = 18792
Dividing both sides by 298:
V2 = 18792 / 298
V2 ≈ 63 L
Therefore, V2 is approximately equal to 63 L.