Directions for Set-Up
Before Pressing Go, which way do you think the cart will move? (None, Right, Left)
Why does the cart move that way?
What is the sum & direction of the forces?
(example: 70 Left)
Place 1 small blue guy on the very end of the left rope & 1 small red guy on the very end of the right rope
Before pressing Go, the cart will move to the right. This is because there is a greater net force acting on the cart in the right direction.
The cart moves to the right because the net force acting on it is greater in that direction. The net force is determined by adding up all the individual forces acting on the cart.
The sum and direction of the forces can vary depending on the specific setup and weight distribution of the cart.
To determine the sum and direction of the forces, we need to consider the forces acting on the cart. In this scenario, there are two forces acting on the cart - one from the small blue guy and one from the small red guy. The force exerted by each guy can be represented as a vector.
Let's assume that the force exerted by the small blue guy is 30 units to the left and the force exerted by the small red guy is 40 units to the right.
To determine the net force, we need to add these vectors together. When adding vectors, we need to consider both their magnitude (the value) and their direction. The magnitude of the force exerted by the small blue guy is 30 units, and its direction is to the left. The magnitude of the force exerted by the small red guy is 40 units, and its direction is to the right.
To add these vectors, we can subtract the magnitude and add the directions since they are in opposite directions. The result is 40 - 30 = 10 units to the right.
Therefore, the sum and direction of the forces acting on the cart is 10 units to the right.