Nobel and Maaham are wearing inline skates. Nobel has a mass of 62kg and pushes Maaham, whose
mass is 54kg. Maaham accelerates at 1.2m/s2
[left]. Assume that no friction acts on either person.
a) Determine the force that Nobel exerts on Maaham.
b) Determine Nobels acceleration.
a) To determine the force that Nobel exerts on Maaham, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
F = m * a
Here, Nobel is pushing Maaham, so the force exerted by Nobel on Maaham is the force required to accelerate Maaham.
So, the force that Nobel exerts on Maaham is:
F = 54 kg * 1.2 m/s^2
= 64.8 N
Therefore, Nobel exerts a force of 64.8 N on Maaham.
b) To determine Nobel's acceleration, we can use Newton's second law of motion again. In this case, Nobel is being pushed back by the reaction force from pushing Maaham. Since there is no friction acting on either person, the reaction force will be equal in magnitude and opposite in direction to the force exerted on Maaham.
So, the force exerted on Nobel by Maaham is also 64.8 N.
Using Newton's second law of motion again:
F = m * a
64.8 N = 62 kg * a
Dividing both sides by 62 kg:
a = 64.8 N / 62 kg
≈ 1.05 m/s^2
Therefore, Nobel's acceleration is approximately 1.05 m/s^2.
To answer these questions, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.
a) Determine the force that Nobel exerts on Maaham:
The force exerted by Nobel on Maaham is equal in magnitude and opposite in direction to the force that Maaham exerts on Nobel. Since both Nobel and Maaham are on inline skates, there is no friction involved.
We know the mass of Maaham is 54 kg, and her acceleration is 1.2 m/s^2. Let's denote the force exerted by Nobel on Maaham as F.
According to Newton's second law, we can calculate the force:
F = m * a
F = 54 kg * 1.2 m/s^2
F = 64.8 Newtons
Therefore, Nobel exerts a force of 64.8 Newtons on Maaham.
b) Determine Nobel's acceleration:
To find Nobel's acceleration, we can use the same equation, but with Nobel's mass and the force exerted by Maaham on Nobel. However, we first need to calculate the force exerted by Maaham on Nobel, which is equal in magnitude to the force exerted by Nobel on Maaham.
The force exerted by Maaham on Nobel is also 64.8 Newtons.
Now, we can calculate Nobel's acceleration:
F = m * a
64.8 N = 62 kg * a
64.8 N / 62 kg ≈ 1.048 m/s^2
Therefore, Nobel's acceleration is approximately 1.048 m/s^2.
To determine the force that Nobel exerts on Maaham, you can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
a) Force exerted by Nobel on Maaham:
The mass of Maaham is given as 54 kg, and her acceleration is given as 1.2 m/s². Therefore, we can calculate the force using the formula:
Force = Mass × Acceleration
Force = 54 kg × 1.2 m/s²
Force = 64.8 Newtons
So, Nobel exerts a force of 64.8 Newtons on Maaham.
b) To determine Nobel's acceleration, we need to consider the forces acting on Nobel. In this case, the only force acting on Nobel is the force he exerts on Maaham. Since there is no friction involved, there are no opposing forces.
Using the same formula as before, but substituting Nobel's mass and the force as variables:
Force = Mass × Acceleration
64.8 Newtons = 62 kg × Acceleration
Rearranging the equation to solve for Acceleration:
Acceleration = Force / Mass
Acceleration = 64.8 N / 62 kg
Acceleration ≈ 1.05 m/s²
So, Nobel's acceleration is approximately 1.05 m/s².