Kader and Cam are sharing the cost of dinner in a ratio of 2:5.If Kader only wants to pay a maximum of $20, then how much can the dinner cost at most?
Let's assume that the cost of dinner is $x.
According to the given ratio, Kader's share is 2 and Cam's share is 5.
So, Kader's share of the cost will be (2/7) * x.
Since Kader wants to pay a maximum of $20, we have the inequality: (2/7) * x ≤ $20.
Multiplying both sides of the inequality by 7 gives: 2x ≤ $140.
Dividing both sides of the inequality by 2 gives: x ≤ $70.
Therefore, the dinner can cost at most $70.
To find out the maximum cost of dinner, we need to determine the larger part of the ratio. In this case, the larger part is 5.
Since Kader wants to pay a maximum of $20, we can set up a proportion to find out the maximum cost of the dinner.
The ratio of Kader's payment to the total cost of dinner can be written as: 2/5 = 20/x, where x is the total cost of dinner.
To solve for x, we can cross multiply:
2x = 5 * 20
2x = 100
Now divide both sides by 2 to solve for x:
x = 100/2
x = 50
Therefore, the dinner can cost at most $50.
To find out the maximum cost of dinner, we need to determine the ratio of Kader's payment to the total cost of dinner.
The ratio of Kader's payment to the total cost is 2:7, which is the sum of the ratio of Kader's payment to Cam's payment (2:5) and the ratio of Cam's payment to the total cost (5:7).
Let's assume that the total cost of dinner is x.
Therefore, Kader's payment would be (2/7) * x, and we know that it should be a maximum of $20.
Let's set up an equation to solve for x:
(2/7) * x = $20
To isolate x, we can multiply both sides of the equation by 7/2:
x = ($20) * (7/2)
x = $140/2
x = $70
So, the maximum cost of dinner can be $70.