Given f(x)=4x^2-10x-3, according to the remainder theorem, f(2) can be found by finding the remainder Of which of the fallowing division quotients?
(4x^2-10x-3)/2
(4x^2-10x-3)/(x-2)
(4x^2-10x-3)/(x+2)
(4x^2-10x-3)/x
According to the remainder theorem, if we divide f(x) by (x - c), where c is a constant, the remainder will be equal to f(c).
Therefore, to find f(2), we need to divide f(x) by (x - 2) and find the remainder.
So, the correct division quotient is (4x^2-10x-3)/(x-2).
According to the remainder theorem, to find f(2), we need to find the remainder of dividing f(x) by (x-2).
Therefore, the correct division quotient is:
(4x^2-10x-3)/(x-2)
According to the remainder theorem, if we divide a polynomial f(x) by a linear factor (x-a), the remainder is equal to f(a). So, to find f(2) using the remainder theorem, we need to find the remainder when dividing the polynomial (4x^2-10x-3) by (x-2).
Let's divide (4x^2-10x-3) by (x-2) to find the remainder:
2x+4
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(x-2) | 4x^2 - 10x - 3
- (4x^2 - 8x)
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-2x - 3
When dividing (4x^2-10x-3) by (x-2), the remainder is -2x - 3.
Therefore, the correct division quotient to find f(2) using the remainder theorem is (4x^2-10x-3)/(x-2).