One molecule of bromine (B*r_{2}) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products? (1 point)
six
O four
Othree
Otwo
Ite
Ite
Iter
The reaction you mentioned is between bromine (Br2) and potassium chloride (KCl). The balanced equation for the reaction is:
2KCl + Br2 -> 2KBr + Cl2
From the balanced equation, we can see that two molecules of potassium chloride (KCl) react with one molecule of bromine (Br2) to produce two molecules of potassium bromide (KBr) and one molecule of chlorine (Cl2).
In the products, there are two potassium bromide molecules, which each contain one potassium (K) atom and one bromine (Br) atom, totaling 2 potassium (K) atoms and 2 bromine (Br) atoms.
There is also one chlorine (Cl2) molecule, which contains two chlorine (Cl) atoms.
Therefore, in total, there are 2 + 2 + 2 = 6 atoms in the products.
So, the correct answer is "six".
To determine the number of atoms in the products, we first need to write out the chemical equation for the reaction:
1 Br2 + 2 KCl -> 2 KBr + 1 Cl2
From the balanced equation, we can see that 1 molecule of bromine (Br2) reacts with 2 molecules of potassium chloride (KCl) to form 2 molecules of potassium bromide (KBr) and 1 molecule of chlorine (Cl2).
Now, let's count the number of atoms in each product:
- KBr: 1 potassium (K) atom and 1 Bromine (Br) atom, totaling 2 atoms
- Cl2: 2 chlorine (Cl) atoms
Adding the atoms together, we have a total of 2 + 2 = 4 atoms in the products.
Therefore, the correct answer is "four."
To determine the number of atoms in the products of the reaction, we need to first write out the balanced chemical equation.
The given reaction is:
1 molecule of bromine (Br2) + 2 molecules of potassium chloride (KCI) → ?
The balanced equation for this reaction is:
1 Br2 + 2 KCI → 2 KBr + 1 Cl2
From the balanced equation, we can see that:
- 1 molecule of bromine (Br2) reacts to form 2 molecules of potassium bromide (KBr).
- 2 molecules of potassium chloride (KCl) react to form 1 molecule of chlorine gas (Cl2).
Therefore, the products of the reaction are:
2 molecules of potassium bromide (KBr) and 1 molecule of chlorine gas (Cl2).
To determine the number of atoms in the products, we need to count the number of atoms for each element:
In 2 molecules of potassium bromide (KBr):
- There are 2 potassium (K) atoms.
- There are 2 bromine (Br) atoms.
In 1 molecule of chlorine gas (Cl2):
- There are 2 chlorine (Cl) atoms.
Adding up the number of atoms in the products, we get:
2 potassium (K) atoms + 2 bromine (Br) atoms + 2 chlorine (Cl) atoms = 6 atoms in total.
So, the correct answer is "six."