According to this diagram, what is the net force on this object?
Responses
0 newtons
0 newtons
8 newtons
8 newtons
22 newtons
22 newtons
36 newtons
36 newtons
Small box with dot in the middle. Arrows originate at dot. Arrow up and Arrow down are same length. Arrow up labeled F sub norm equals 20 N and Arrow down labeled F sub grav equals 20 N. Arrow to the right is longer than arrow to the left. Arrow to the right is labeled F sub app equals 22 N and arrow to the left is labeled F sub frict equals 14 N.
The net force on the object can be found by subtracting the force in the opposite direction from the force in the desired direction.
F_net = F_app - F_frict
F_net = 22 N - 14 N
F_net = 8 N
Therefore, the net force on the object is 8 newtons.
To determine the net force on the object, we need to consider the magnitudes and directions of the forces acting on it.
From the diagram, we see that there are four forces acting on the object:
1. F_norm (upward force) = 20 N
2. F_grav (downward force due to gravity) = 20 N
3. F_app (to the right) = 22 N
4. F_frict (to the left) = 14 N
To calculate the net force, we need to consider the vector sum of these forces.
Since the forces F_norm and F_grav are equal in magnitude but opposite in direction, they cancel each other out. So, the net vertical force is 0 N.
The forces F_app and F_frict are acting in opposite directions. To calculate the net horizontal force, we can subtract the magnitude of the frictional force from the applied force:
Net horizontal force = F_app - F_frict
Net horizontal force = 22 N - 14 N
Net horizontal force = 8 N
Therefore, the net force on the object is 8 newtons (in the horizontal direction).
To determine the net force on the object, we need to consider the forces acting on it and their directions. Looking at the diagram, we can identify four forces:
1. The force of gravity (F_sub_grav) acting downward with a magnitude of 20 Newtons.
2. The normal force (F_sub_norm) acting upward with a magnitude of 20 Newtons. This force is equal in magnitude to the force of gravity when the object is on a flat surface.
3. The applied force (F_sub_app) acting to the right with a magnitude of 22 Newtons.
4. The force of friction (F_sub_frict) acting to the left with a magnitude of 14 Newtons.
Since the forces are acting in opposite directions, we need to consider their magnitudes as well.
To find the net force, we subtract the forces acting in the opposite direction:
Net force = (F_sub_app - F_sub_frict)
Net force = (22 N - 14 N)
Net force = 8 Newtons
Therefore, the net force on the object is 8 Newtons.