the emiprical formula of an organic compound is C1H2O1. If the emiprical formula mass is 30. Find the percentage composition of the elements in the compound
To find the percentage composition of the elements in the compound, we need to determine the molar masses of the elements.
The empirical formula indicates that there is 1 carbon atom, 2 hydrogen atoms, and 1 oxygen atom in the compound.
The molar mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of hydrogen (H) is approximately 1.008 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
To calculate the percentage composition of each element:
1. Calculate the total molar mass of the empirical formula:
- (1 carbon atom * 12.01 g/mol) + (2 hydrogen atoms * 1.008 g/mol) + (1 oxygen atom * 16.00 g/mol) = 30.03 g/mol (approximately)
2. Calculate the percentage composition of each element:
- Carbon: (12.01 g/mol / 30.03 g/mol) * 100% = 39.97%
- Hydrogen: (2 * 1.008 g/mol / 30.03 g/mol) * 100% = 6.73%
- Oxygen: (16.00 g/mol / 30.03 g/mol) * 100% = 53.30%
Therefore, the percentage composition of the elements in the compound is approximately:
- Carbon: 39.97%
- Hydrogen: 6.73%
- Oxygen: 53.30%
To find the percentage composition of elements in the compound, we need to calculate the masses of each element first.
Given:
Empirical formula: C1H2O1
Empirical formula mass: 30
The empirical formula mass can be calculated by adding the atomic masses of the elements:
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
Empirical formula mass = (1 * C) + (2 * H) + (1 * O)
30 = 12.01 + (2 * 1.01) + 16.00
Now, let's calculate the masses of each element in the compound:
Mass of Carbon (C) = (1 * 12.01 g/mol) = 12.01 g/mol
Mass of Hydrogen (H) = (2 * 1.01 g/mol) = 2.02 g/mol
Mass of Oxygen (O) = (1 * 16.00 g/mol) = 16.00 g/mol
Next, we will calculate the percentage composition of each element in the compound by using the formula:
Percentage composition = (Mass of element / Empirical formula mass) * 100
Percentage composition of Carbon (C) = (12.01 g/mol / 30 g/mol) * 100 = 40.03%
Percentage composition of Hydrogen (H) = (2.02 g/mol / 30 g/mol) * 100 = 6.73%
Percentage composition of Oxygen (O) = (16.00 g/mol / 30 g/mol) * 100 = 53.23%
Therefore, the percentage composition of the elements in the compound with the empirical formula C1H2O1 is approximately:
Carbon: 40.03%
Hydrogen: 6.73%
Oxygen: 53.23%
To find the percentage composition of the elements in the compound, we need to calculate the molecular formula using the given empirical formula and empirical formula mass.
1. Start by calculating the empirical formula mass:
The empirical formula mass is the sum of the atomic masses of the elements in the empirical formula.
The atomic masses are:
- Atomic mass of carbon (C) = 12.01 g/mol
- Atomic mass of hydrogen (H) = 1.01 g/mol
- Atomic mass of oxygen (O) = 16.00 g/mol
So, the empirical formula mass = (1*12.01) + (2*1.01) + (1*16.00) = 12.01 + 2.02 + 16.00 = 30.03 g/mol (rounded to two decimal places)
2. Calculate the molecular formula mass:
The molecular formula mass is the actual mass of the compound. The empirical formula mass represents the mass of one empirical formula unit.
Given that the empirical formula mass is 30 g/mol, we can infer that one empirical formula unit weighs 30.03 g.
3. Determine the ratio between the empirical formula mass and molecular formula mass:
The ratio between the molecular formula mass and the empirical formula mass gives us the number of empirical formula units in the molecular formula.
Molecular formula mass / Empirical formula mass = Number of empirical formula units
Let's assume x as the number of empirical formula units:
Molecular formula mass / 30.03 = x
Since the empirical formula mass is equal to the molecular formula mass, the ratio is 1:
1 = x
Therefore, the molecular formula is the same as the empirical formula: C1H2O1.
4. Calculate the percentage composition:
To calculate the percentage composition of an element, divide the mass of that element in the compound by the molecular formula mass and multiply by 100.
Percentage of carbon (C) = (mass of carbon / molecular formula mass) * 100
Percentage of hydrogen (H) = (mass of hydrogen / molecular formula mass) * 100
Percentage of oxygen (O) = (mass of oxygen / molecular formula mass) * 100
In this case, since there is only one atom of each element in the formula, the percentage composition will be equal to the atomic masses of each element:
Percentage of carbon (C) = (12.01 / 30.03) * 100 ≈ 39.98%
Percentage of hydrogen (H) = (2.02 / 30.03) * 100 ≈ 6.73%
Percentage of oxygen (O) = (16.00 / 30.03) * 100 ≈ 53.29%
Therefore, the percentage composition of the elements in the compound C1H2O1 is approximately:
- 39.98% carbon (C)
- 6.73% hydrogen (H)
- 53.29% oxygen (O)