The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth. what is the answer?
To find the length of the edge of the square base, we can use the Pythagorean theorem.
Let's denote the length of each side of the square base as "x".
According to the Pythagorean theorem, we have:
x^2 + (321 ft)^2 = (436.5 ft)^2
x^2 + 103041 ft^2 = 190882.25 ft^2
x^2 = 190882.25 ft^2 - 103041 ft^2
x^2 = 87841.25 ft^2
Taking the square root of both sides of the equation, we get:
x = √(87841.25 ft^2)
x ≈ 296.2 ft
Therefore, the length of the edge of the square base is approximately 296.2 ft when rounded to the nearest tenth.
To find the length of the edge of the square base, you can use the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the height and the slant height form a right triangle. Let's call the length of the edge of the square base "x".
Applying the Pythagorean Theorem, we have:
x^2 + 321^2 = 436.5^2
Simplifying this equation:
x^2 + 103041 = 190612.25
Subtracting 103041 from both sides:
x^2 = 876571.25
Taking the square root of both sides to solve for x:
x = sqrt(876571.25) ≈ 936.3 ft
Therefore, the length of the edge of the square base is approximately 936.3 ft (rounded to the nearest tenth).
To find the length of the edge of the square base of the Pyramid in Memphis, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the height of the pyramid is one side, the slant height is the hypotenuse, and the length of the edge of the square base is the other side. So, we have:
Length of the edge of the square base^2 + Height^2 = Slant height^2
Let's denote the length of the edge of the square base as "x."
Then we have:
x^2 + 321^2 = 436.5^2
Let's solve for x:
x^2 + 103041 = 190820.25
x^2 = 190820.25 - 103041
x^2 = 87779.25
Taking the square root of both sides:
x ≈ √87779.25
x ≈ 296.1
Therefore, the length of the edge of the square base of the Pyramid in Memphis, rounded to the nearest tenth, is approximately 296.1 feet.