The triangle is translated 2 units left and 4 units up. What are the coordinates of the vertices of △J′K′L′, the translated triangle?
To translate a point in the coordinate plane, you need to add (or subtract) the same amounts from the x-coordinate and y-coordinate of the original point.
If the triangle's vertices are J(x, y), K(x, y) and L(x, y), then the coordinates of the translated vertices △J'K'L' would be:
J' = (x - 2, y + 4)
K' = (x - 2, y + 4)
L' = (x - 2, y + 4)
To find the coordinates of the vertices of the translated triangle △J'K'L', we need the original coordinates of the vertices of the triangle △JKL.
Let's assume the original coordinates of the vertices of △JKL are as follows:
J(x1, y1)
K(x2, y2)
L(x3, y3)
To translate the triangle 2 units left and 4 units up, we need to subtract 2 from the x-coordinate of each vertex and add 4 to the y-coordinate of each vertex.
The new coordinates of the vertices of △J'K'L' will be:
J'(x1 - 2, y1 + 4)
K'(x2 - 2, y2 + 4)
L'(x3 - 2, y3 + 4)
Therefore, the coordinates of the vertices of △J'K'L', the translated triangle, are:
J'(x1 - 2, y1 + 4)
K'(x2 - 2, y2 + 4)
L'(x3 - 2, y3 + 4)
To find the coordinates of the vertices of the translated triangle, you can simply apply the same translation to the coordinates of the original triangle.
Let's assume the coordinates of the original triangle △JKL are J(x1, y1), K(x2, y2), and L(x3, y3).
To translate the triangle 2 units to the left, subtract 2 from the x-coordinates of each vertex.
To translate the triangle 4 units up, add 4 to the y-coordinates of each vertex.
Therefore, the coordinates of the translated triangle △J'K'L' are:
J'(x1 - 2, y1 + 4)
K'(x2 - 2, y2 + 4)
L'(x3 - 2, y3 + 4)
Now, you have the coordinates of the new vertices of the translated triangle.