Use the information in the table to answer the question. Bond Bond Energy (kJ/mol) H–Cl 427 Cl–Cl 242 H–H 435 Hydrogen and chlorine gases react to produce hydrochloric acid according to the reaction. H2 + Cl2 → 2HCl How much total bond energy, in kJ/mol, is in the products of the reaction?
677 854 427 435
pick an option
The equation H2 + Cl2 → 2HCl shows that two moles of HCl are formed from one mole each of H2 and Cl2.
To find the total bond energy in the products, we need to sum up the bond energies of all the bonds broken and formed.
In the reactants (H2 and Cl2), we have two H-H bonds and one Cl-Cl bond.
Bond energy for H-H bond = 435 kJ/mol
Bond energy for Cl-Cl bond = 242 kJ/mol
In the products (2HCl), we have two H-Cl bonds.
Bond energy for H-Cl bond = 427 kJ/mol
Total bond energy in the products = 2 * (bond energy of H-Cl bond) = 2 * 427 kJ/mol = 854 kJ/mol
Therefore, the correct option is 854 kJ/mol.
To calculate the total bond energy in the products of the reaction, we need to determine the bonds broken and formed during the reaction.
In the given reaction, H2 and Cl2 react to form 2HCl. This means that two H-Cl bonds are formed.
To calculate the total bond energy, we need to add together the bond energy of the H-Cl bonds formed.
The bond energy of an H-Cl bond is given as 427 kJ/mol.
Since 2 H-Cl bonds are formed, the total bond energy in the products of the reaction is:
2 H-Cl bonds * 427 kJ/mol = 854 kJ/mol.
Therefore, the correct answer is 854 kJ/mol.
To determine the total bond energy in the products of the reaction, we need to calculate the bond energy of each bond in the hydrochloric acid molecule (HCl) and then multiply it by the number of those bonds in the products.
From the information given in the table:
- The bond energy for H–Cl bond is 427 kJ/mol.
- Since there are two H–Cl bonds in 2HCl, the total bond energy of the H–Cl bonds is 427 kJ/mol * 2 = 854 kJ/mol.
Therefore, the correct answer is 854 kJ/mol.