what denminator for 21/3=40/_ would make these ratios proportional?
To make the ratios proportional, we need to find the denominator that would make the fractions equal when simplified.
First, simplify the given fraction 21/3, which equals 7.
So, we have 7/1 = 40/x.
To find the missing value, cross-multiply:
7x = 40*1
7x = 40
Finally, divide both sides by 7 to solve for x:
x = 40/7
Therefore, the denominator that makes the ratios proportional is 7, resulting in a fraction of 40/7.
To make the ratios proportional, we need to find the missing denominator.
Given: 21/3 = 40/_
First, cross-multiply the given ratios:
21 * _ = 3 * 40
Next, simplify the equation:
21_ = 120
Now, solve for the missing denominator by dividing both sides of the equation by 21:
_ = 120 ÷ 21
_ ≈ 5.71
Therefore, the missing denominator that would make the ratios proportional is approximately 5.71.
To make the ratios proportional, we need to find the missing denominator that would satisfy the proportion:
21/3 = 40/x
Firstly, let's simplify the given ratio:
21 ÷ 3 = 7
So, the ratio 21/3 is equal to 7. Now, we can rewrite the equation with the simplified ratio:
7 = 40/x
To find the missing denominator, we will cross-multiply:
7x = 40
To solve for x and determine the missing denominator, divide both sides of the equation by 7:
7x/7 = 40/7
x = 40/7
Therefore, the denominator that would make the ratios proportional is 7.