The average tectonic plate moves at the rate of 0.006 m per year. How many meters would it move in 2 * 10 ^ 6 years? Write the answer in scientific notation, expressed to the exact decimal place. (1 point)
M
To find the distance the tectonic plate moves in 2 * 10^6 years, we can multiply the rate of movement per year (0.006 m) by the number of years (2 * 10^6).
0.006 m/year * 2 * 10^6 years = 0.012 * 10^6 m
We can simplify this expression to scientific notation by moving the decimal point to the left one place and adjusting the exponent accordingly:
0.012 * 10^6 m = 1.2 * 10^5 m
Therefore, the tectonic plate would move 1.2 * 10^5 meters in 2 * 10^6 years.
To find the distance a tectonic plate would move in 2 * 10^6 years, we can multiply the average speed of 0.006 m/year by the number of years.
Distance = Speed * Time
Distance = 0.006 m/year * 2 * 10^6 years
To multiply 0.006 by 2 * 10^6, we multiply the numbers first and then add the exponents:
0.006 * 2 = 0.012
10^6 * 10^6 = 10^(6+6) = 10^12
Therefore, the distance the tectonic plate would move in 2 * 10^6 years is 0.012 * 10^12 meters.
Expressed in scientific notation, this is written as 1.2 * 10^10 meters.
To find how many meters the tectonic plate would move in 2 * 10^6 years, we can multiply the rate at which it moves per year (0.006 m/year) by the number of years.
0.006 m/year * 2 * 10^6 years = 0.006 * 2 * 10^6 m
To multiply 0.006 by 2, we get 0.012.
0.012 * 10^6 m
Since we are multiplying by 10^6, we would move the decimal point 6 places to the right.
Therefore, the answer is 12,000,000 meters, expressed in scientific notation as 1.2 * 10^7 meters.