Identify the relation that is also a function.
A.
{(3, −1), (3, 1), (3, 0), (0, 2)}
B.
{(5, 6), (4, 5), (5, 8), (4, 0)}
C.
{(−2, 1), (−1, 2), (1, 4), (−3, −2)}
D.
{(6, 4), (6, −4), (10, 5), (10, −5)}
The relation that is also a function is option C: {(−2, 1), (−1, 2), (1, 4), (−3, −2)}.
The relation that is also a function is option C. {(−2, 1), (−1, 2), (1, 4), (−3, −2)}. This is because for every input (x-value) in the relation, there is exactly one output (y-value). In other words, each x-value is paired with only one y-value.
To identify the relation that is also a function, we need to check if each input (x-value) has only one corresponding output (y-value).
Let's analyze each option:
A. {(3, −1), (3, 1), (3, 0), (0, 2)}
In this case, the x-value '3' has multiple y-values (-1, 1, 0), which means it does not satisfy the definition of a function.
B. {(5, 6), (4, 5), (5, 8), (4, 0)}
Again, the x-value '5' has multiple y-values (6, 8). Therefore, B is not a function.
C. {(−2, 1), (−1, 2), (1, 4), (−3, −2)}
This relation seems to satisfy the definition of a function. Each x-value is associated with only one y-value.
D. {(6, 4), (6, −4), (10, 5), (10, −5)}
Once again, the x-values '6' and '10' have multiple y-values. So, D is not a function.
Based on this analysis, the relation that is also a function is option C.