Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide ( CO2
). According to the law of conservation of matter, how many atoms are present in this reaction?(1 point)
Responses
20
20
30
30
15
15
10
The correct answer is 30.
To determine the number of atoms present in the reaction, we need to consider the chemical formula of carbon dioxide (CO2). In one molecule of carbon dioxide, there is one carbon atom (C) and two oxygen atoms (O). Given that 10 molecules of carbon dioxide are formed, we can calculate the total number of atoms as follows:
Number of carbon atoms = 10 molecules × 1 atom/molecule = 10 atoms
Number of oxygen atoms = 10 molecules × 2 atoms/molecule = 20 atoms
Therefore, there are a total of 10 carbon atoms and 20 oxygen atoms present in this reaction. The correct answer is option 1: 20.
To determine the number of atoms present in the reaction, we need to consider the number of atoms involved in the reactants and compare it to the number of atoms in the product.
Given that 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2), we can analyze the number of atoms in each compound:
- One molecule of carbon dioxide (CO2) contains one atom of carbon (C) and two atoms of oxygen (O).
- With 10 molecules of carbon dioxide formed, we have 10 atoms of carbon (10 x 1) and 20 atoms of oxygen (10 x 2).
So, the total number of atoms present in this reaction is 10 atoms of carbon + 20 atoms of oxygen, which equals 30 atoms.
Therefore, the correct answer is 30.