The sides of a pallelogram in fig 14.6 are given in cm with side is 2x+y, 4x-3, 3y+2x, 5y-8. Find x and y and the perimeter of the parallelogram

To find x and y, we need to equate the opposite sides of the parallelogram:

2x + y = 3y + 2x
4x - 3 = 5y - 8

Simplifying the first equation, we get:
2x - 2x = 3y - y
0 = 2y

Therefore, y = 0.

Using this value of y in the second equation:
4x - 3 = -8
4x = -8 + 3
4x = -5
x = -5/4

So, x = -5/4 and y = 0.

Now, let's find the perimeter of the parallelogram.

The length of one side of the parallelogram is 2x + y = 2(-5/4) + 0 = -5/2.

The length of the adjacent side is 4x - 3 = 4(-5/4) - 3 = -5 - 3 = -8.

The other two sides can be found using the same approach.

So, the perimeter of the parallelogram is:
Perimeter = (2)(-5/2) + (-8) + (3)(0) + (5)(0)
Perimeter = -5 - 8 + 0 + 0
Perimeter = -13 + 0 + 0
Perimeter = -13.

Therefore, the perimeter of the parallelogram is -13 cm.
Note: Typically, lengths and perimeters are expressed as positive values.

To find the values of x and y, we can equate the given expressions for the sides of the parallelogram.

The sides of the parallelogram are:

Side 1: 2x + y
Side 2: 4x - 3
Side 3: 3y + 2x
Side 4: 5y - 8

Since opposite sides of a parallelogram are equal in length, we can equate the expressions for the sides:

2x + y = 4x - 3 (Equation 1)
3y + 2x = 5y - 8 (Equation 2)

Let's solve Equation 1 for x:

2x + y = 4x - 3

Bringing all the x terms to one side and the constant terms to the other side:

2x - 4x = - 3 - y
-2x = -3 - y
2x = y + 3 (Equation 3)

Now, let's solve Equation 2 for y:

3y + 2x = 5y - 8

Bringing all the y terms to one side and the constant terms to the other side:

3y - 5y = -8 - 2x
-2y = -8 - 2x
2y = 8 + 2x (Equation 4)

We now have two equations, Equation 3 and Equation 4, which describe the relationship between x and y. We can now solve these equations simultaneously to find the values of x and y.

Let's substitute the value of y from Equation 3 into Equation 4:

2y = 8 + 2x
2(y + 3) = 8 + 2x
2y + 6 = 8 + 2x
2y = 2x + 2

Now, substitute this value of 2y into Equation 4:

2x + 2 = 8 + 2x
2 = 8

This equation is not true for any value of x or y, so there is no solution.

Therefore, we cannot find the values of x and y.

As for the perimeter of the parallelogram, we cannot determine it without the values of x and y.

To find the values of x and y, we need to set up a system of equations using the given information about the sides of the parallelogram:

Side 1: 2x + y
Side 2: 4x - 3
Side 3: 3y + 2x
Side 4: 5y - 8

Since our parallelogram has opposite sides that are equal in length, we can set up the following equations:

2x + y = 4x - 3 [Equation 1]
3y + 2x = 5y - 8 [Equation 2]

We can solve this system of equations to find the values of x and y. Let's solve it step by step:

Step 1: Simplify Equation 1
2x + y = 4x - 3
Subtract 2x from both sides:
y = 2x - 3x - 3
y = -x - 3 [Equation 3]

Step 2: Simplify Equation 2
3y + 2x = 5y - 8
Subtract 3y from both sides:
2x = 2y - 8
Divide both sides by 2:
x = y - 4 [Equation 4]

Now we have two equations:
y = -x - 3 [Equation 3]
x = y - 4 [Equation 4]

We can substitute Equation 4 into Equation 3 to solve for y:

y = -(y - 4) - 3
y = -y + 4 - 3
2y = 1
y = 1/2

Now we substitute the value of y back into Equation 4 to solve for x:

x = (1/2) - 4
x = -7/2

So, x = -7/2 and y = 1/2.

To find the perimeter of the parallelogram, we sum up the lengths of all four sides:

Perimeter = Side 1 + Side 2 + Side 3 + Side 4
Perimeter = (2x + y) + (4x - 3) + (3y + 2x) + (5y - 8)

Now, substitute the values we found for x and y:

Perimeter = (2*(-7/2) + 1/2) + (4*(-7/2) - 3) + (3*(1/2) + 2*(-7/2)) + (5*(1/2) - 8)

Simplify the expression:

Perimeter = (-7 + 1/2) + (-14 - 3) + (3/2 - 7) + (5/2 - 8)
Perimeter = (-14/2 + 1/2) + (-17) + (-11/2) + (-16/2)
Perimeter = (-13/2) + (-17) + (-11/2) + (-8)
Perimeter = -13/2 - 34/2 - 11/2 - 16/2
Perimeter = -74/2
Perimeter = -37

Since a negative perimeter doesn't make sense, please double-check the given side lengths of the parallelogram or re-verify the equations to get the correct solution.